word sorting using array swap

Dear Friends

I wrote a code that prompt user to give 5 different words or name and than it will print given names or words in ascending order .code is running successfully but I am using Dec.C++ 4.9.9.2 and in this compiler my code is not running it close the window after getting 5 strings.please help me in this code.

Code:

#include<iostream>
#include<string>
#include<stdio.h>
#include<conio.h>
using namespace std;
int main()
{
 char array[5];
 char temp;
 for(int i=0;i<5;i++)
 {
  cout<<"enter string :"<<i+1<<": ";
  cin>>array[i];
    }
 for(int i=0;i<5-1;i++)
 {
  for(int j=i;j<5;j++)
  {
   if(array[i]>array[j])
   {
    temp=array[i];
    array[i]=array[j];
    array[j]=temp;
   }
  }
 }
 cout<<"sorting string\n";
 for(int i=0;i<5;i++)
 {
 cout<<array[i]<<endl;

 

sorry i forgot to mention that the code is running in trubo c but not in Dev C++.

 

Hi Yasiir,

I'm not familiar with Dev C++, but I can try with the program part.

Is this the complete code?
I can see that the last for loop is not completed.
Also the int main is not completed.

I don't know if this will be true for Dev C++ or not,
Does Dev C++ open a new window for I/O of the program?
If Yes, then I believe that after you display the sorted results, you'll have to wait for user input (action) to close the window, so that the last output is displayed to the user and the window still remains open, instead of the window closing directly, in which case the results will be displayed but it will not be visible to the user because the window gets closed.

Let me know If I'm right or not...

- Nimesh

 

Dear Nameesh

Yes you are right that that Dev C++ open a new window for IO of the programme and it is also true that it close directly after propmting 5 character.However I tried more and got the solution.I just add one more header file i.e stdio.h and conio.h and getch(); at the end and my code is correct now.But please explain me as I am in beggining of C++.why my window clos directly after taking 5 char.??

Thanks

Code:

#include<iostream>
#include<string>
#include<stdio.h>
#include<conio.h>
using namespace std;
int main()
{
 char array[5];
 char temp;
 for(int i=0;i<5;i++)
 {
  cout<<"enter string :"<<i+1<<": ";
  cin>>array[i];
    }
 for(int i=0;i<5-1;i++)
 {
  for(int j=i;j<5;j++)
  {
   if(array[i]>array[j])
   {
    temp=array[i];
    array[i]=array[j];
    array[j]=temp;
   }
  }
 }
 cout<<"sorting string\n";
 for(int i=0;i<5;i++)
 {
 cout<<array[i]<<endl;
}
 getch();
}

 

It's the normal behavior for the program.

You said to display it, so it displays the output and quits.

How will the program know that the user wants to watch the output for hours and then close the window.

So, we have to write and extra statement, for the user to give an additional input, any input, to indicate that he has done his output viewing and needs to close the window.

So, the statement... getch();

You can also add an output line like... "Press any key to close this window"

 

Thanks sir
I got the point.
I expect you will support me always like this.

Once again thank you.

Yasir