Pointer confusion! URGENT!!

Hi I have got stuck bcos of this unexpected result .. Can someone Aid???

Program:

Code:

#include <stdio.h>

typedef struct tStruct
{
    int a;
    int b;
    int c;
}tStruct;

tStruct *temp1;

void func1(tStruct *node)
{

    temp1 = (tStruct*)malloc(sizeof(tStruct));
    printf("\n Address of the node : %u",temp1);

    node = temp1; // I doubt this part.
    node->a = 1;
    node->b = 2;
    node->c = 3;
    printf("\n Value of a : %u",temp1->a);
    printf("\n Value of b : %u",temp1->b);
    printf("\n Value of c : %u",temp1->c);
}

main()
{
    tStruct *temp=0;
    func1(temp);
    printf("\n Address of the node : %u",temp);
    printf("\n Value of a : %u",temp->a);
    printf("\n Value of b : %u",temp->b);
    printf("\n Value of c : %u",temp->c);
}

Result:

Address of the node : 2500
Value of a : 1
Value of b : 2
Value of c : 3
Address of the node : 0
Value of a : 0
Value of b : 0
Value of c : 30036

I need to view the values of the the node in the main() function. But am unsuccessful.

Thanks in Advance.

Cheers,
Kart.

 

Hi,
From main you are passing temp by value, to achieve desired result you should pass temp by address.
Like

Code:

#include <stdio.h>

typedef struct tStruct
{
    int a;
    int b;
    int c;
}tStruct;

tStruct *temp1;
void func1(tStruct **node)
{

    temp1 = (tStruct*)malloc(sizeof(tStruct));
    printf("\n Address of the node : %u",temp1);

    *node = temp1; // I doubt this part.
    (*node)->a = 1;
    (*node)->b = 2;
    (*node)->c = 3;
    printf("\n Value of a : %u",temp1->a);
    printf("\n Value of b : %u",temp1->b);
    printf("\n Value of c : %u",temp1->c);
}


main()
{
    tStruct *temp=0;
    func1(&temp);
    printf("\n Address of the node : %u",temp);
    printf("\n Value of a : %u",temp->a);
    printf("\n Value of b : %u",temp->b);
    printf("\n Value of c : %u",temp->c);
}

 

thanks Dinesh.. it indeed solved the problem!!