there's something wrong.. :/

Hello, I think there's something wrong in my code.
I made a program converting °C-°F .
the formula is °F = (1.8*°C) + 32

Here's the code:

Code:

#include <stdio.h>
#include <conio.h>

int main()
{
    int C;
    int F;
    printf("Enter the value of °C: ");

    scanf("%d", &C);

    total = (1.8 * C) + 32;

    printf("°F=%d", F);

    getch();

}

when I enter the value of C as 2. the answer should be 35.6 .. but it only shows 35.. it doesn't have any decimals.. what should I do?? thank you in advance if someone will help..

 

ahh no.. it's wrong.. here's the correct one..

Code:

#include <stdio.h>
#include <conio.h>

int main()
{
    int C;
    int F;
    printf("Enter the value of °C: ");

    scanf("%d", &C);

    F = (1.8 * C) + 32;

    printf("°F=%d", F);

    getch();

}

 

TO get the output in decimals we need to use the 'float' data-type .

Corrected Code :-

Code:

#include <stdio.h>
#include <conio.h>

int main()
{
int C;
[COLOR="Red"]float F;[/COLOR]
printf("Enter the value of °C: ");

scanf("%d", &C);

F = (1.8 * C) + 32;

[COLOR="Red"]printf("°F=%f", F);[/COLOR]

getch();

}

Output :-

Code:

Enter the value of C: 2
F=35.599998

 

what u(jam 143) have writen is absolutely correct but...............
there is only one controversy that your answer will not be printed in decimals
because int range is-32768to 32767 so it cannot accept decimal values
so we use other data type called "float" whose range is -3.4e-38 to -3.4e+38
so we can use it

just print the answer as printf("F=%f",f);
you will get the required answer

 

thank you for help.. for the both of you.. really big help.. thank you so much.. )

 

Iam sorry if am wrong about the above program how can int f;
give you floating point value if u write %f.

 

yes sir,
it will show abnormal termination
what i mean in before post is to cast the data type
for example x=(float)y;

 

ok ok thats fine

HI I AM RAMAKRISHNA