Pointer to memory address

I have a small problem. Following a pointer to a particular segment: offset point to (for example, 0041Ch)
How can I now put this address to a pointer?

 

But once the trial here is not whether the white Abder:

Code:

char * pointer, 
pointer = 0x0041;

 

Segment and offset the smell of DOS programming, so all that follows is not a standard C + +, but Borland / Turbo C + + specific (DJGPP perhaps?)

Code:

#include <dos.h> 
char far * my_far_pointer = MK_FP(0, 0x41C); /* make far pointer 0000:041c */

 

As soon as I can I create a variable with no prob on the address space access. Can someone tell me why it does not go without a variable?

I get the following error: expression must be a pointer or a zero constant.

So far, no solution works ...

who has other solutions ... just tell me

 

the relevant code would still be useful ...

 

Well, I would say, because you may not be the storage area
belongs.

 

Well, my current program does not have anything with the code you need to do now. I would just say exactly, I always read the values of exactly this location. With pure assembler can I do that ... But everything must go without asm. Can I ever passed from one hand to the pointer location?

 

Yes, but you can not read or write it because you like the storage
area is not heard.

 

I have such a result that works under Linux, you have other systems under test.

mem_addr int = 0x0041;
ptr_of_int int *,
long * ptr_of_long;
char * ptr_of_char;

ptr_of_int = (int *) mem_addr;

ptr_of_long = (long *) mem_addr;

ptr_of_char = (char *) mem_addr;

 

I would say that depends entirely on the OS