Here is my problem I can't figure out how to loop two variable at the same while they increment at the same time with the same increment I can't explain myself I will just give an example: Code: The increment is 50 T1 T2 300 350 350 400 400 450 450 500 500 550 550 600 600 650 650 700 700 750 750 800 800 850 850 900 900 950 950 1000 Here is my program Code: #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> int main(){ int i,j,T; printf("Input T: "); scanf("%d",&T); for(j=300+T;j<=1000;j+=T) for(i=300;i<=(1000-T);i+=T){ printf("T1 = %d and T2 = %d\n",i,j); } getche(); }
I checked your code in linux machine.so I have changed few lines. In your code there is no need to two loops.You can do that using a single loop. Code: #include <stdio.h> #include <math.h> #include <stdlib.h> #include <string.h> int main(){ int i,j,T; printf("Input T: "); scanf("%d",&T); for(i=300;i<=950;i+=T) { j=i+50; printf("T1 = %d and T2 = %d\n",i,j); } }
do this:- Code: #include <stdio.h> #include <conio.h> int main(){ int i,j,T; printf("Input T: "); scanf("%d",&T); for(i=300,j=350;i<=1000 && j<=1000 ;i+=T,j+=T) { printf("T1 = %d and T2 = %d\n",i,j); } getch(); return 0; }
Thanks techgeek.in but i have another question..:happy: if the user wanted to input numbers with decimal numbers how will i do that??
Code: #include <stdio.h> int main(){ float T1,T2,end1,increment; printf("first variable="); scanf("%f",&T1); printf("second variable="); scanf("%f",&T2); printf("increment for first and second variable="); scanf("%f",&increment); printf("end when first variable is>="); scanf("%f",&end1); printf("The increment is %f",increment); printf("\n T1 T2\n"); while(T1<end1){ T1+=increment; T2+=increment; printf("%10.3f %10.3f\n",T1,T2); } getchar(); getchar(); } with this code you can have T1,T2 and increment as demical numbers
u can try this:- Code: #include <stdio.h> #include <conio.h> int main(){ float i,j,T; printf("Input T: "); scanf("%f",&T); for(i=300.0,j=350.0;i<=1000.0 && j<=1000.0 ;i+=T,j+=T) { printf("T1 = %f and T2 = %f\n",i,j); } getch(); return 0; }
Now I upgraded the program.. thanks to all your help!! but i have a last question how can I set the range or the stopper to T2 to 1000K because the table of the ideal gas is for only 300K to 1000K so beyond that range in not applicable.. Code: //This program generates a table for the specific internal energy //and the specific enthalpy of Methane from 300K to 1000K using the //specific heat variations listed on Table A.21 #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> int main(){ int QA; float T1=300,T2,end1,inc; double a=3.826,b=-3.979,c=24.558,d=-22.733,e=6.963; double A,B,C,D,E,H,U,R=8.3143,M=16.04,i=10; char error[128]; do{ do{ system("cls"); printf("Enter the Increment in Temperature: "); scanf("%s",&error); inc=atof(error); if(inc<=0){ system("cls"); printf("Invalid Input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); } }while(inc<=0); T2=T1+inc; end1=1000-inc; printf("The increment is %.3f\n\n",inc); printf("\nInitial Temperature\tFinal Temperature\tEnthalpy\tInternal Energy\n"); while(T1<=end1){ T1+=inc; T2+=inc; A=a*(T2-T1); B=(1/pow(i,3))*(b/2)*(pow(T2,2)-pow(T1,2)); C=(1/pow(i,6))*(c/3)*(pow(T2,3)-pow(T1,3)); D=(1/pow(i,9))*(d/4)*(pow(T2,4)-pow(T1,4)); E=(1/pow(i,12))*(e/5)*(pow(T2,5)-pow(T1,5)); H=(R/M)*(A+B+C+D+E); U=(R/M)*((A+B+C+D+E)-(T2-T1)); printf("%10.3f K\t\t%10.3f K\t\t%.3f kJ/kg\t%.3f kJ/kg\n",T1,T2,H,U); } do{//This used to ask the user if s/he wants to repeat the evaluation printf("\n\nDo you want to repeat the computation or Quit?\n"); printf("[1] Yes\n"); printf("[2] Quit\n"); scanf("%s",&error); QA=atoi(error); switch(QA){ case 1: break; case 2://Return to the selection screen exit(1); break; default://The program redirects invalid inputs to this part system("cls"); printf("Invalid input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); break; } }while(QA>2||QA<1); }while(QA==1); getche(); }
see this:- Code: //This program generates a table for the specific internal energy //and the specific enthalpy of Methane from 300K to 1000K using the //specific heat variations listed on Table A.21 #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> int main(){ int QA; float T1=300,T2,end1,inc; double a=3.826,b=-3.979,c=24.558,d=-22.733,e=6.963; double A,B,C,D,E,H,U,R=8.3143,M=16.04,i=10; char error[128]; do{ do{ system("cls"); printf("Enter the Increment in Temperature: "); scanf("%s",&error); inc=atof(error); if(inc<=0){ system("cls"); printf("Invalid Input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); } }while(inc<=0); T2=T1+inc; end1=1000-inc; printf("The increment is %.3f\n\n",inc); printf("\nInitial Temperature\tFinal Temperature\tEnthalpy\tInternal Energy\n"); while(T1<=end1){ T1+=inc; T2+=inc; A=a*(T2-T1); B=(1/pow(i,3))*(b/2)*(pow(T2,2)-pow(T1,2)); C=(1/pow(i,6))*(c/3)*(pow(T2,3)-pow(T1,3)); D=(1/pow(i,9))*(d/4)*(pow(T2,4)-pow(T1,4)); E=(1/pow(i,12))*(e/5)*(pow(T2,5)-pow(T1,5)); H=(R/M)*(A+B+C+D+E); U=(R/M)*((A+B+C+D+E)-(T2-T1)); printf("%10.3f K\t\t%10.3f K\t\t%.3f kJ/kg\t%.3f kJ/kg\n",T1,T2,H,U); } do{//This used to ask the user if s/he wants to repeat the evaluation printf("\n\nDo you want to repeat the computation or Quit?\n"); printf("[1] Yes\n"); printf("[2] Quit\n"); scanf("%s",&error); QA=atoi(error); switch(QA){ case 1: break; case 2://Return to the selection screen exit(1); break; default://The program redirects invalid inputs to this part system("cls"); printf("Invalid input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); break; } }while(QA>2||QA<1); }while(QA==1 && T2<=1000); getche(); }
correct the above code like this Code: ....................... switch(QA){ case 1: [COLOR=Red]T1=300;//add this T2=0;//add this[/COLOR] break; case 2://Return to the selection screen exit(1); ...................... Code: }while(QA>2||QA<1); }while(QA==1 && T2<[COLOR=Red]=[/COLOR]1000); [COLOR=Red]//i am not sure but i think you must remove = [/COLOR] getche(); }
I figured it out already..hehe the only thing that is needed to be change is this Code: T1=300-inc; T2=300; end1=1000-inc; Program Code: //This program generates a table for the specific internal energy //and the specific enthalpy of Methane from 300K to 1000K using the //specific heat variations listed on Table A.21 #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> int main(){ int QA; float T1=300,T2,end1,inc; double a=3.826,b=-3.979,c=24.558,d=-22.733,e=6.963; double A,B,C,D,E,H,U,R=8.3143,M=16.04,i=10; char error[128]; do{ do{ system("cls"); printf("Enter the Increment in Temperature: "); scanf("%s",&error); inc=atof(error); if(inc<=0){ system("cls"); printf("Invalid Input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); } }while(inc<=0); T2=T1+inc; end1=1000-inc; printf("The increment is %.3f\n\n",inc); printf("\nInitial Temperature\tFinal Temperature\tEnthalpy\tInternal Energy\n"); while(T1<=end1){ T1+=inc; T2+=inc; A=a*(T2-T1); B=(1/pow(i,3))*(b/2)*(pow(T2,2)-pow(T1,2)); C=(1/pow(i,6))*(c/3)*(pow(T2,3)-pow(T1,3)); D=(1/pow(i,9))*(d/4)*(pow(T2,4)-pow(T1,4)); E=(1/pow(i,12))*(e/5)*(pow(T2,5)-pow(T1,5)); H=(R/M)*(A+B+C+D+E); U=(R/M)*((A+B+C+D+E)-(T2-T1)); printf("%10.3f K\t\t%10.3f K\t\t%.3f kJ/kg\t%.3f kJ/kg\n",T1,T2,H,U); } do{//This used to ask the user if s/he wants to repeat the evaluation printf("\n\nDo you want to repeat the computation or Quit?\n"); printf("[1] Yes\n"); printf("[2] Quit\n"); scanf("%s",&error); QA=atoi(error); switch(QA){ case 1: break; case 2://Return to the selection screen exit(1); break; default://The program redirects invalid inputs to this part system("cls"); printf("Invalid input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); break; } }while(QA>2||QA<1); }while(QA==1); getche(); }
