Seeking Help for Code Explanation

Discussion in 'Assembly Language Programming (ALP) Forum' started by IamNew, Dec 5, 2011.

  1. IamNew

    IamNew New Member

    Joined:
    Nov 29, 2011
    Messages:
    4
    Likes Received:
    0
    Trophy Points:
    0
    Hi there,

    I am new to c programming and I am current studying the example codes. I am having difficulty to understand the line
    Code:
     lcd_data(s+48);
    . I wish to know what does this line meas and what will it done.

    Here is the full codes:
    Code:
    //Program to interface IR sensor using ADC 0804. Set Vref =1.5v for ADC 0804
    
    #include<reg51.h>
    #define port P3
    #define adc_input P1
    #define dataport P0
    #define sec 100
    sbit rs = port^0;
    sbit rw = port^1;
    sbit e = port^2;
    
    sbit wr= port^3;
    sbit rd= port^4;
    sbit intr= port^5;
    
    int test_final=0 ,shift=0;
    
    void delay(unsigned int msec ) // Time delay function
    {
    int i ,j ;
    for(i=0;i<msec;i++)
      for(j=0; j<1275; j++);
    }
    
    void lcd_cmd(unsigned char item) // Function to send command to LCD
    {
    dataport = item;
    rs= 0;
    rw=0;
    e=1;
    delay(1);
    e=0;
    return;
    }
    
    void lcd_data(unsigned char item)  // Function to send data to LCD
    {
    dataport = item;
    rs= 1;
    rw=0;
    e=1;
    delay(1);
    e=0;
    return;
    }
    
    void lcd_data_string(unsigned char *str) // Function to send string to LCD
    {
    int i=0;
    while(str[i]!='\0')
    {
      lcd_data(str[i]);
      i++;
      delay(1);
    }
    return;
    }
    
    void convert()
    {
    int s;
    lcd_cmd(0x81);
    delay(2);
    lcd_data_string("output:");
    s=test_final/100;
    test_final=test_final%100;
    lcd_cmd(0x8a);
    if(s!=0)
    lcd_data(s+48);
    else
    lcd_cmd(0x06);
    s=test_final/10;
    test_final=test_final%10;
    lcd_data(s+48);
    lcd_data(test_final+48);
    lcd_data(' ');
    if(shift>16)
    {
    lcd_cmd(0xc0+(shift-1));
    lcd_data_string("       ");
    shift=0; 
    }
    lcd_cmd(0xc0+(shift-1));
    lcd_data(' ');
    lcd_cmd(0xc0+shift);
    lcd_data_string("CALIBRATE IT");
    delay(30);
    }
    
    void main()
    {
    adc_input=0xff;
    lcd_cmd(0x38);  //2 Line, 5X7 Matrix
    lcd_cmd(0x0c);  //Display On, Cursor Blink
    delay(2);
    lcd_cmd(0x01);  // Clear Screen
    delay(2);
    lcd_cmd(0x81);  // Setting cursor to first position of first line
    delay(2);
    while(1)
    {
      shift++;
      delay(1);
      rd=1;
      wr=0;
      delay(1);
      wr=1;
      while(intr==1);
      rd=0;
      test_final=adc_input;
      delay(1);
      intr=1;
      convert();
    }
    }
    Please guide me through and I will appreciate it very much.:worried:
     
  2. xpi0t0s

    xpi0t0s Mentor

    Joined:
    Aug 6, 2004
    Messages:
    3,009
    Likes Received:
    203
    Trophy Points:
    63
    Occupation:
    Senior Support Engineer
    Location:
    England
    s is a number from 0-9, and 48 is the ASCII character code of the character '0'. So s+48 converts 0-9 to '0'-'9' - this is done 3 times, once for the hundreds digit (so presumably test_final is in the range 0-999), once for the 10s and once for the units. If the first two are zero then it does lcd_cmd(0x06) instead, which I presume moves the cursor one step to the right, so that a value of 36 is not displayed as '036'.
     

Share This Page

  1. This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
    By continuing to use this site, you are consenting to our use of cookies.
    Dismiss Notice