pattern program for square

hello frnds, please help me with this program.

Q : Ypu are given an odd number as input and you have to write a function to draw alternative squares of 1s and 0s.

Sample : input number : 7

Output : 1 1 1 1 1 1 1
1 0 0 0 0 0 1
1 0 1 1 1 0 1
1 0 1 0 1 0 1
1 0 1 1 1 0 1
1 0 0 0 0 0 1
1 1 1 1 1 1 1

Prototype for the function : void drawsquare(int input);

Please provide generic code for any odd number entered.

 

something like this maybe

Code:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

void drawsquare(int input);

int reverse(char *);
    char before[100]="";
    char after[100]="";
    
int main(){
    int squares;

    printf("\n number of squares=");
    scanf("%d",&squares);getchar();
    drawsquare(squares);
    getchar();
    return 0;
}

void drawsquare(int squares){
    int i,j;
for (i=1;i<=squares;i++){
        if (i>=squares/2+2){
        int length1=strlen(before);
        if (length1-1>=0){
            before[strlen(before)-1]='\0';
            strcpy(after,before); 
            reverse(after);
        }
        }
        printf("\n%s",before);
        for (j=0;j<squares-strlen(before)*2;j++){
            printf("%d",i%2);
        }
        printf("%s",after);
        if (i<squares/2+2){
            char temp[10];
            itoa(i%2,temp,10);
            strcat(before,temp); 
            strcpy(after,before); 
            reverse(after);   
        }  
    }
}


int reverse(char * after1) {
char temp[100];
int i;
for (i=0;i<strlen(after1);i++)
    temp[i]=after1[strlen(after1)-i-1];
temp[strlen(after1)]='\0';
strcpy(after1,temp);
  return 0;
}

 

Nice one. Here's another solution. BTW OP, you should also work on your own ideas, not just hand this stuff in. Plagiarism is a serious offence in academic circles (and tutors can spot it a mile off).

Code:

void drawsquare(int input)
{
	int maxN=(input-1)/2;
	printf("input=%d; maxN=%d\n",input,maxN);
	for (int y=-maxN; y<=maxN; y++)
	{
		for (int x=-maxN; x<=maxN; x++)
		{
			int px=(x<0) ? -x : x;
			int py=(y<0) ? -y : y;
			char digit='0';
			for (int M=1; M<=maxN; M+=2)
			{				
				if ((px==M && py<=M)) || (py==M && px<=M))
					digit='1';
			}
			putchar(digit);
		}
		putchar('\n');
	}
	putchar('\n');
}