Generation of lucky nos from a given list of nos.

THIS IS D PROGRAM TO GENERATE LUCKY NUMBERS OUT OF A GIVEN NUMBERS

FIRSTLY SUPPOSE CONSIDER 10 ITEMS
1 2 3 4 5 6 7 8 9 10
FIRSTLY EACH 2ND ELEMENT IS DELETED THEN WE GET
1 3 5 7 9
THEN EACH 3RD ELEMENT IS DELETED
1 3 7 9
THEN EACH 4TH ELEMENT WILL BE DELETED THEN WE GET
1 3 7
NOW EACH 5TH ELEMENT IS DELETED AS THERE IS NO 5TH ITEM WE GET
1 3 7
THE ABOVE NOS
1 3 7
ARE CALLED LUCKY NOS

THIS GIVEN PROGRAM IS WRITTEN IN C SO TRY IT ONCE
CODE:C

Code:

#include"stdio.h"
#include"conio.h"
void main()
{
  int i,k=0,p=2,t=0,n;int a[100];
  printf("enter the size of the array:\n");
  scanf("%d",&n);
  printf("enter the elements of the array\n");
  for(i=0;i<n;i++)
  {
    scanf("%d",&a[i]);
  }
  printf(" The Sequence Of Lucky Nos Per Step Are:\n");
  for(i=0;i<n;i++)
  {
     printf("%d",a[i]);
     printf("\t");
  }

  while(1)
  {
     t=0;
    for(i=0;i<n;i++)
  {

     if(a[i]!=32767)
     {
        k++;
        if(k==p)
        {
          a[i]=32767;t++;
          k=0;
        }

      }
    }
        p++;k=0;
         if(t==0)
         {
              break;
         }
         printf("\n");
            for(i=0;i<n;i++)
        {
            if(a[i]!=32767)
          {
         printf("%d ",a[i]);
         printf("\t");
          }
        }
         printf("\n");



    }
     getch();
 }