This is the program to figure out the day entered on a particular date but remember this code works between the years 1900 to 1999 suppose u enter the date as 5/1/1957 then the day comes out to be saturday so try it out and post ur comments Code: /*this is d program to figure out the day on a particular date entered*/ #include<stdio.h> #include<stdlib.h> #include<conio.h> void main() { clrscr(); int d,m,y,year,month,day,i,n; printf("Enter the date : "); scanf("%d%d%d",&day,&m,&y); if( day>31 || m>12 || (y<1900 || y>=2000) ) { printf("INVALID INPUT"); getch(); exit(0); } year = y-1900; year = year/4; year = year+y-1900; switch(m) { case 1: case 10: month = 1; break; case 2: case 3: case 11: month = 4; break; case 7: case 4: month = 0; break; case 5: month = 2; break; case 6: month = 5; break; case 8: month = 3; break; case 9: case 12: month = 6; break; } year = year+month; year = year+day; d= year%7; switch(d) { case 0: printf("Day is SATURDAY"); break; case 1: printf("Day is SUNDAY"); break; case 2: printf("Day is MONDAY"); break; case 3: printf("Day is TUESDAY"); break; case 4: printf("Day is WEDNESDAY"); break; case 5: printf("Day is THURSDAY"); break; case 6: printf("Day is FRIDAY"); break; } getch(); }
It would be nice if the logic is also explained with post, one can understand what is being done but it is also necessary to know why it is done.
amanbua: it would be good if you fixed this code so that it would work for ANY year, not just 1900-1999. Then post the new code. I don't see much point in the code as it stands; anyone who wants to use it will want it to work for today, and you've had 10 years to fix it to work in this century, so there's no excuse really for it only supporting last century.
