char[][] instead of char*[] in calling a function

Hi All,

I have a function that takes 'char *[]' as parameter:

void myFunc(char *mystrings[]){}

In order to call it I need to create an array of 'char *' and call it. (with malloc and all)

Is there anyways to call this function with char[][] instead of char*[]? Something like this:

char mystring[2][20];

strcpy(mystring[0], "This is first line");
strcpy(mystring[1], "This is second line");
myFunc(mystring);


I've tried myFunc(*mystring) and myFunc(**mystring) already.

Thanks

 

Code:

#include <stdio.h>

/* a generic method to handle variable no of strings of variable length - */

void genericstrhandler(char *strarray, int numstr, int stringlen);

char strings[ 5 ][ 10 ] =
							{
								"one",
								"two",
								"three",
								"four",
								"five"
							};
void main()
{
	genericstrhandler(strings[ 0 ], 5, 10);
}

void genericstrhandler(char *strarray, int numstr, int stringlen)
{
	char *p;
	int i;
	
	for( i = 0, p = strarray; i < numstr; i++, p += stringlen )
	{
		printf("%d : %s\n", i, p);
	}
	
}