programme for swapping of two numbers without using temporary varaible

hi frinds lets learn a programme to swap two numbers withouit using temporary variable .
this is in "c"

Code:

/*swapping of two numbers*/

#include<stdio.h>
main()
{
int a,b;
printf("enter the values of a & b");
scanf("%d %d",&a,&b);
printf("the values before swapping are %d,%d",a,b);
a=a+b;
b=a-b;
a=a-b;
printf("now the values after swapping are %d,%d",a,b);
}

 

Have you googled it

You can get a lot ways of doing that on google.

One of them is
a = a + b;
b = a - b;
a = a - b;

 

Thanks for providing this code.

 

lol was helpful. but im having trouble trying to imagine a situation where i wont be able to use a temp var. and why do u prefer scans an print to cout<< and cin

 

it's a tricky question in interviews for a job as a programmer.

 

hey wht r u saying kemnet i dint get u

 

no nothing. i was just trying to imagine a situation where id love this code since i wont be able to use a Temporary Variable. but that got cleared up thanks

 

hey u !
i hadnt googled it i have just learnt this trick ya i agree tht there are several methods to do it i have just mentioned one of them okk

 

hi frinds this can also be done in differnt methods
i would lyk to provide an alternate method instead of previous one as



a=a*b;
b=a/b;
c=a/b;
okk
hope this will be helpful:p

 

no nothing. i was just trying to imagine a situation where id love this code since i wont be able to use a Temporary Variable. but that got cleared up thanks

 

if b=0 what will happen?