Go4Expert - In code C, How can I erase special characters from a char array?

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In code C, How can I erase special characters from a char array?

I have this code:

Code:

int readConfig(char *IP, int *p, char Myfile[]){

char dir[32];

char pto[32];

char c='a';

FILE *fp;

int i=0;



if((fp=fopen(Myfile,"r"))==NULL){

return -1;

}

while(c!=EOF && c!='\n'){

c=getc(fp);

if(c!=EOF && c!='\n'){

dir[i++]=c;



}

}



i=0;

c='a';



while(c!=EOF && c!='\n'){

c=getc(fp);

if(c!=EOF && c!='\n'){

pto[i++]=c;

}

}



*puerto=atoi(pto);

strcpy(IP, dir);

return 0;

}

and the file contains this information: 255.255.255.255
5555

Well, when I print the IP value, this is the result
IP: 255.255.255.255fhv��

How can I do for fix it??? I want that only print: IP: 255.255.255.255

Thanks!!!!

Re: In code C, How can I erase special characters from a char array?

Because your 5555 is converted into ASCII as that character.

Re: In code C, How can I erase special characters from a char array?

> Well, when I print the IP value, this is the result
> IP: 255.255.255.255fhv��
You don't append a \0 to the string you build up, so you get a random amount of trailing junk until the print function just happens to find a \0.

Also, your c variable should be an int if you want to compare it with EOF properly.
Consider this loop a simplification (and safer).

Code:

int c;

while ( i < 31 && (c=getc(fp)) != EOF && c != '\n' ) {

  dir[i++]=c;

}

dir[i] = '\0';

But this very near to what fgets() does for you anyway, so perhaps consider using that to read a line rather than inventing it yourself one character at a time.