Go4Expert - function without return type.

how the operator function i.e. operator const char * const() has no return type but still returning and the code compile successfully.

Code:

namespace Edu {

        class TestBase {

                public:

                        TestBase() { }

                        const char * const GetMessage() const { return "Edu::TestBase()" ; }

                        operator const char * const () const { return this->GetMessage() ; };

        };



        class TestDerived : public TestBase {

                public:

                        TestDerived() { }

                        operator const char * const () const { return "Edu::TestDerived()" ; };

        };



        void Funct( const char * const = "Hello, C++" );

};



void Edu::Funct( const char * const msg ) {

        std::cout << msg << std::endl;

}



int main() {



        const Edu::TestBase ob_base ;

        const Edu::TestDerived ob_derived ;



        std::cout << ob_base << std::endl;

        std::cout << ob_derived << std::endl;



        Edu::Funct( ob_derived ) ;

        Edu::Funct( ob_base ) ;

        Edu::Funct( "Hi from C++ !!" );



        return 0;



}