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pawanjoshi

27Sep2012 17:52

Scope of character pointer and character array in a function

Hi,

Following are two programs which behave differently for same situtaion.

Code:

 

#include<stdio.h>

char *somfun()

{

char *t="pawan";

return t;

}

int main()

{

        puts(somfun());

}

Output : pawan

Code:

 

#include<stdio.h>

char *somfun()

{

char t[]="pawan";

return t;

}

int main()

{

        puts(somfun());

}

output : garbage value

Both variable inside function "somfun" are having local scope even after that first program is printing the value of t...how is it possible???????

xpi0t0s

29Sep2012 13:46

Re: Scope of character pointer and character array in a function

Neither is correct, because in both cases t is on the stack and invalid after the function returns.

This is correct, but you must remember to free the memory some time later otherwise this will leak memory:

Code:

char *morefun()

{

  char *t=malloc(6*sizeof(char));

  strcpy(t,"pawan");

  return t;

}

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