Go4Expert - access 'typedef'ed member function

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access 'typedef'ed member function

Hi folks,
I am learning member function pointers, wrote following program to understand typedef of function (of other class eg: test) inside other class(eg: exam) and then its access.:smug:

I have tried to use (e.*m)(8) but its gave
err:‘m’ was not declared in this scope

Could you please tell me how to call function 'add' using e.m
I have added comments inline for reference

Code:



#include<iostream>

using namespace std;



class test

{

public:

int add(int k){cout<<"test::add"<<endl;

return k+1;

}



};



class exam

{

public:

typedef int (test::*ptr)(int);

ptr m;

};



int main()

{

exam e;

test t;

e.m = &test::add;

(e.m)(8); //Err:must use ‘.*’ or ‘->*’ to call pointer-to-member function in ‘e.exam::m (...)’, e.g. ‘(... ->* e.exam::m) (...)’



 /** followed (function_ptr)(arg) . what is the correct way to call add using e.m **/

return 0;

}

Re: access 'typedef'ed member function

U need to mention he class name of which the add() function is the member...

Modify line
(e.m)(8);
To
t .*(e.m) (8)

Re: access 'typedef'ed member function

Please consider this on

U need to mention he class name of which the add() function is the member...

Modify line
(e.m)(8);
To
(t .*(e.m)) (8)

Re: access 'typedef'ed member function

thank you debugEnthu, its working :)