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Problem of declaration in C language

Today ,I have read the
<Expert C Programming,Deep C Secrets>,
Chapter 3.Unscrambling Declarations in C.
The author introduce the declaration of a little complicated function,then he left another exercise:

Code:

char *(*(c[10]))(int **p);

the answer is given at the of the Chapter 3

However, I am uncertain about the "c[10]",
the book is said:"c is an array[0...9] of pointer to a function returning a pointer-to-char",
I am thinking...
Is there a 10 function pointers ?
Could some master give me a example to show how to use the
char *(*(c[10]))(int **p);
in a C Program?
Thank you very much!

Re: Problem of declaration in C language

Something like this?

Code:

#include <stdio.h>



char *(*(c[10]))(int **p);



char strf0[] = "function0";



char *f0(int **p)

{

        (void) p;

        return strf0;

}



int main(int argc, char** argv){

        c[0] = f0;

        printf("%s\n",f0(0));

        return 0;

}

Pieter Beyens
Bytelead

Re: Problem of declaration in C language

Quote:

Originally Posted by PieterBeyens (Post 93581)

Something like this?

Code:

#include <stdio.h>



char *(*(c[10]))(int **p);



char strf0[] = "function0";



char *f0(int **p)

{

    (void) p;

    return strf0;

}



int main(int argc, char** argv){

    c[0] = f0;

    printf("%s\n",f0(0));

    return 0;

}

Pieter Beyens
Bytelead

Yea, nice example.