![]() |
question on CONSTRUCTOR
what will happen if we define a constructor in protected scope in a class?
for eg class some { int x; protected: some() { x=90; } }; |
Re: question on CONSTRUCTOR
The constructor is never inherited by the derived class, so it doesnt matters wherever u write the constructor.
|
Re: question on CONSTRUCTOR
Quote:
i am not inheriting it i am using only it only in single class and i wil creat an object to it,then wat is the output? |
Re: question on CONSTRUCTOR
well in this case, a compiler error will be thrown. Because u r trying to create a class object which is global to the code whereas the constructor is protected in the class.
|
Re: question on CONSTRUCTOR
If you're not deriving then don't use protected, because it only makes sense in the context of a derived class. Use private or public instead then your intent is clear. By using protected in a class that is not to be derived you are intentionally obfuscating the meaning of your code.
Public is visible to all, private is visible only to the class, and protected is visible to the class and its derivatives. So this is the same as a private constructor, which means only the class itself and its friends can create an object of that class. Code:
class someerror C2248: 'some::some' : cannot access protected member declared in class 'some' |
Re: question on CONSTRUCTOR
This can be fixed by making test16 a friend:
Code:
class some |
Re: question on CONSTRUCTOR
other method using inheritence
Code:
Class A |
| All times are GMT +5.5. The time now is 14:03. |