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How to convert this C array code to MIPS Assembly language?

Hi all I'm working on a problem involving translating an example C array code into the MIPS version, but I'm not quite sure how to do it right. Here is the sample code:

example: int count(int a[], int n, int x) {

int res=0;
int i;
for(i=0;i!=n;i++)
if(a[i]==x)
res=res+1;
return res;
}

Here is what I have so far with my code according to what I understand. Any assistance would be appreciated!

move $t0, $zero # register t0 = 0
move $t1, $zero # register t1 = 0

loop: sll $t2,$t0,2 #t2 = i * 4
add $t3,$a0,$t2 # $t3 = address of array a[]
sw $zero, 0($t2) # array a[] = 0

bne $ # check the end of the loops

Re: How to convert this C array code to MIPS Assembly language?

here is a small example that i made for you.
i do not use it as a function but as a single program.
modify it to your needs.

Code:

.data

str1: .asciiz "count="

.align 2

a: .space 5



.text 

.globl main



main:

         #create the array

         la $9,a #load address  of the array

         addi $8,$0,5 #value to store

         sw $8,0($9) #store data in array a[0]=5

         addi $9,$9,4 #next element

         addi $8,$0,5 #value to store

         sw $8,0($9) #store data in array a[1]=5

         addi $9,$9,4 #next element

         addi $8,$0,5 #value to store

         sw $8,0($9) #store data in array a[2]=5

         addi $9,$9,4 #next element

         addi $8,$0,6 #value to store

         sw $8,0($9) #store data in array a[3]=6

         addi $9,$9,4 #next element

         addi $8,$0,7 #value to store

         sw $8,0($9) #store data in array a[4]=7

         addi $9,$9,4 #next element

        add $14,$0,$0 #res=0;

        addi $16,$0,10 #n=5;

        addi $17,$0,5 #x=5;

        add $18,$0,$0#i=0; in order to start loop from 0

        la $9,a #load address  of the array

        loop: #for 

        lw $15 ,0($9) #a[i]

        addi $9,$9,4 #next element

        bne $15,$17,notequal

        addi $14,$14,1 #res=res+1;

        notequal: 

        addi $18, $18, 1 # i=i+1;

        bne $18, $16, loop #next

        #print result

           addi $2,$0,4

           la $4,str1

           syscall #count=

           addi $2,$0,1

           add $4,$0,$14 

           syscall# res

Re: How to convert this C array code to MIPS Assembly language?

You can do the MIPS conversion using ctomips.com I used it to check against my homework. It works pretty well.