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-   -   Mathemagic | 20 Nov, 2009 (http://www.go4expert.com/contests/mathemagic-20-nov-2009-t20149/)

shabbir 20Nov2009 19:07

Mathemagic | 20 Nov, 2009
 
You have a custom operation ^ and the following equation x ^ y = 2x + y,

Now what is the value of a in 2 ^ a = a ^ 3

BTW I also don't know the answer and is a question of some paper.

pankaj.sea 20Nov2009 20:29

Re: Mathemagic | 20 Nov, 2009
 
a=1 :thinking:

shabbir 21Nov2009 10:59

Re: Mathemagic | 20 Nov, 2009
 
Would you explain the answer

sameer_havakajoka 21Nov2009 11:22

Re: Mathemagic | 20 Nov, 2009
 
x^y = 2x +y

2^a = a^3

=======================

2^a = 2(2)+a
2^a = 4+a

=================

a^3 = 2(a)+3

===============

4+a = 2a+3

2a-a=4-3

a=1

pankaj.sea 21Nov2009 12:20

Re: Mathemagic | 20 Nov, 2009
 
Quote:

Originally Posted by sameer_havakajoka (Post 60508)
x^y = 2x +y

2^a = a^3

=======================

2^a = 2(2)+a
2^a = 4+a

=================

a^3 = 2(a)+3

===============

4+a = 2a+3

2a-a=4-3

a=1

Yes! This is same or the correct the explanation of my answer!


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