C puzzle
how will you check the relation of two numbers (greater or lesser) without using Relational operators ?????? :D:D:D:nice::nice:

Re: C puzzle
By comparing them using IF Else

Re: C puzzle
for comparing u need relational operator na :):):) , use ifelse.. but the question is without relational operators how will u decide the relation between two numbers....? please

Re: C puzzle
You can do it using the following logic:
Let us assume the numbers to be x and y. Code:
if(x/y) If you divide a smaller number by a greater number the result will be "zero". case 1: x<y (x/y) results "0", in turn makes the condition if(o) => if(false) and so the else part is executed. case 2:x>y (x/y) results some positive value, in turn makes the condition to if(true) and so if part is executed. 
Re: C puzzle
hmm.. it's correct:) good...... but take the worst case , take 'x' and 'y' to be same......... so let us assume x=90 , y=90 , is 90>90 or 90<90 , this statement is false..... so in ur logic , the ur if() will be true for u....... actually it mustt be false.........
and my question is for alll operators , and not only fot > & < , also for >= , <= and ==..... and i ll say a clue , in all relational operators only one thing will change entirely, by changing that u can write the logic and check it...... thank u 
Re: C puzzle
Quote:

Re: C puzzle
just u try it sir..... it's simple..... :):):):):)

Re: C puzzle
If the two numbers are same, we can find that out using this XOR condition:
Code:
if(x^y) If x and y are equal, then condition becomes if(0). 
Re: C puzzle
HMMM... for equality this is correct , for lesser or greater wat will be the logic.... :) :) :nice:

Re: C puzzle
I have already posted the result for lesser or greater :D

All times are GMT +5.5. The time now is 22:23. 