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shabbir 2Oct2009 19:49

Perfect Squares | 2 Oct 2009
 
Find a,b which satisfy the following
  • a,b are both greater than 1
  • a and b are not equal.
  • a^2 + 3b and b^2 + 3a are perfect square.
^ denotes power

nimesh 2Oct2009 20:30

Re: Perfect Squares | 2 Oct 2009
 
a = 11
b = 16 (or vice versa)

11 and 16 both are greater than 1
11 and 16 are not equal

a^2 + 3b = 11^2 + 3*16 = 121+48 = 169
b^2 + 3a = 16^2 + 3*11 = 256+33 = 289

169 and 289 are perfect squares of 13 and 17 resp

shabbir 3Oct2009 11:00

Re: Perfect Squares | 2 Oct 2009
 
Bingo


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