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shabbir 29Sep2009 21:43

Length of Pole | 29 Sep 2009
 
Pole is in a lake. Half of the pole is under the ground, One-third of it is covered by water. 8 ft is out of the water.

What could be the possible length of the pole?

sameer_havakajoka 29Sep2009 21:58

Re: Length of Pole | 29 Sep 2009
 
48

sameer_havakajoka 29Sep2009 22:20

Re: Length of Pole | 29 Sep 2009
 
48ft is correct

Solution:

Fraction of pole in the ground = 1/2
Fraction of pole covered by water = 1/3
Fraction of pole in the ground and covered by water = 1/2 + 1/3 = (3 + 2)/6 = 5/6
Fraction of pole out of water = 1 - 5/6 = 1/6
Thus, one-sixth of the pole (out of water) is 8 ft.
So, total length of pole = 48 ft.

It may be noted that:
Length of pole in the ground = 48/2 = 24 ft.
Length of pole covered by water = 48/3 = 16 ft.
Length of pole out of water = 8 ft.


The problem may also be solved by setting up the following equation: x/2 + x/3 + 8 = x
where x denotes the total length of the pole in ft.
The equation may be solved as shown below.
5x/6 + 8 = x
8 = x - 5x/6 = x/6
x/6 = 8 or x = 48.

shabbir 30Sep2009 09:25

Re: Length of Pole | 29 Sep 2009
 
Bingo

sameer_havakajoka 30Sep2009 12:04

Re: Length of Pole | 29 Sep 2009
 
yeyeyey, thanks sab.


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