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vignesh1988i 23Sep2009 08:55
C programming
 
write a C program , to find whether a number is ODD or EVEN without using Control structures , looping, arrays, functions , operators(namely relational, arithmetic , logical )??????????:):):):):):)

SaswatPadhi 23Sep2009 19:05
Re: C programming
 
OK, we can't use relational, arithmetic, logical operators, but we can use bit-wise and operator.

Code: CPP
if(A&1) {printf("%d is odd\n", A);}
else      {printf("%d is even\n", A);}

vignesh1988i 25Sep2009 02:51
Re: C programming
 
but control structures(if... else) also should not be used...... but ur logic is right....
try that!!!!!:)

SaswatPadhi 25Sep2009 16:23
Re: C programming
 
We can always replace the if...else with the conditional operator <condition> ? <true case> : <false case> .
That way, the code becomes :
Code: CPP
(A&1) ? printf("%d is odd\n", A) : printf("%d is even\n", A);

vignesh1988i 25Sep2009 18:17
Re: C programming
 
hmmmm :)then i ll put my question , in this way... there is a way to print without this conditional operator also.... try:)

thank u

SaswatPadhi 25Sep2009 19:57
Re: C programming
 
Then I would do it this way ;)

Code: CPP
char Result[2][5] = {"EVEN", "ODD"};

printf("%d is %s\n", A, Result[A&1]);

vignesh1988i 26Sep2009 09:46
Re: C programming
 
hmmmm :)..in my question i already said without using arrays toooo u should do it!!!!!!!:):)

xpi0t0s 26Sep2009 12:23
Re: C programming
 
Code:
printf("1 for odd, 0 for even -> %d \n",A&1);
If that still doesn't answer, please copy and paste the ORIGINAL question, not your summary of what you think it says.

vignesh1988i 26Sep2009 12:30
Re: C programming
 
hmmmmmm this is the right answer..... :)

SaswatPadhi 26Sep2009 17:37
Re: C programming
 
Quote:
Originally Posted by vignesh1988i (Post 58000)
hmmmm :)..in my question i already said without using arrays toooo u should do it!!!!!!!:):)
My mistake :p

Quote:
Originally Posted by xpi0t0s (Post 58004)
Code:
printf("1 for odd, 0 for even -> %d \n",A&1);
Nice.


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