Cut the chain  12 Sep 2009
A Man has 23link chain. He lives in a house whose rent is worth one link for one day. What is the fewest number of cuts he can make in the chain for paying rent for each day.

Re: Cut the chain  12 Sep 2009
2 cuts.
He would cut link no. 4 and 11. ( counting from the same end ) :) 
Re: Cut the chain  12 Sep 2009
Explanation ::
After cutting links 4 and 11, he would be left with : (A) Two chains of 1link length each : link 4 and link 11. (B) One chain of 3link length : link 1~3 (C) One chain of 6link length : link 5~10 (D) One chain of 12link length : link 12~23 He then pays the 2 chains in (A) for the first 2 days. On day 3, he gets back the 2 chains and gives (B) chain as rent. Then pays 2 (A) chains for next two days. And gets back 2 (A) chains + the (B) chain on day 6 and gives (C) chain as rent. Then pays the 2 (A) chains and the (B) chain as rent for next 5 days. And gets back all chains and pays the (D) chain as rent. Then, he repeats the above steps till day 23. :) 
Re: Cut the chain  12 Sep 2009
Quote:

Re: Cut the chain  12 Sep 2009
Of course he could have, and so there is no point of all this.
So, obviously I meant that only (one link/day), just I am lazy to type :p OK. Let's have it your way : Explanation :: After cutting links 4 and 11, he would be left with : (A) Two chains of 1link length each : link 4 and link 11. (B) One chain of 3link length : link 1~3 (C) One chain of 6link length : link 5~10 (D) One chain of 12link length : link 12~23 He then pays the 2 chains in (A) for the first 2 days (one chain on each day). On day 3, he gets back the 2 chains and gives (B) chain as rent. Then pays 2 (A) chains for next two days (one chain on each day). And gets back 2 (A) chains + the (B) chain on day 6 and gives (C) chain as rent. Then pays the 2 (A) chains (one chain on each day) for day 7 and 8. On day 9, he pays (B) chain as rent and gets back the 2 (A) chains. He then pays the 2 (A) chains (one chain on each day) for next 2 days (till day 11). And gets back all chains and pays the (D) chain as rent on day 12. Then, he repeats the above steps till day 23. Phew... > 100 chars added. 
Re: Cut the chain  12 Sep 2009
OK Got it.

Re: Cut the chain  12 Sep 2009
Congrs SP :D

Re: Cut the chain  12 Sep 2009
Thanx naimish :happy:

Re: Cut the chain  12 Sep 2009
:welcome: SP :lol:

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