Math Riddle | 17 Jul 2009
 

A bit tricky and interesting as well

x+y+z=0
x^3+y^3+z^3=3
x^5+y^5+z^5=15

x^2+y^2+z^2=?

^ = Power of

Re: Math Riddle | 17 Jul 2009
 

Hey...

x^2+y^2+z^2 =1

Im i right???

Re: Math Riddle | 17 Jul 2009
 

It'd better not be as simple as that...after several hours and sheets of paper I'm just about to give up on solving it with simultaneous equations...

Re: Math Riddle | 17 Jul 2009
 

However that did give me a useful inequality...so I'm going to register a guess, that x^2+y^2+z^2 is an integer and is precisely 6. Just running another, more accurate, test but it'll take a while to produce results.

Re: Math Riddle | 17 Jul 2009
 

Yes that is the right Answer :D

I have the values of x,y,z as well if you want to.

Re: Math Riddle | 17 Jul 2009
 

@ xpi0t0s, Congrs Buddy :)

Re: Math Riddle | 17 Jul 2009
 

Of course X^2+y^2+z^2 can be real even if x, y, z are all complex. But, I'm just curious .. Do these equations have any real solutions ?? :crazy:

Re: Math Riddle | 17 Jul 2009
 

I wonder why I keep getting 60 as the answer. :(

Re: Math Riddle | 17 Jul 2009
 

The answer is 6 and X=3, y=-2 and Z=-1

Re: Math Riddle | 17 Jul 2009
 

But 3^3 + (-2)^3 + (-1) ^3 = 27-8-1 = 18 ?? :crazy:

Further, 3^2 + (-2)^2 + (-1)^2 = 9 + 4 + 1 = 14 ?! :crazy: