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Passing Pointer-To-An-Array Through Function

Hi!
I want to pass a pointer-to-an-array through a function and print the data in the array. I dont know why its giving junks...! Please tell me where i am wrong and how to achieve this? Please note that i want to do this only through function as shown in the code. Pls. help.

Here is the code:

Code:

 

char *NameList[] = { "Father", "Mother"};

main()

{

  int i;

  Function(NameList);  //Pointer To The Array Is Passed Through The Function

}

 

Function(char *ArrayPointer)

  {

    int i;

    for (i=0; i < 2; i++)

      {

        printf("\nName: %s %s", ArrayPointer[i]);  // Why It is not fetching the data?

      }

  }

Re: Passing Pointer-To-An-Array Through Function

Hi..tppramod,

First let me clarify you that Array always passes to functions through pointer,the base address of array...As you are beginner,I have two solutions for you.

Solution 1::

Code:

char *pNameList = 0;

char NameList[][10] = { "Father", "Mother"};



void Function(char *ArrayPointer)

{

    int i;

    for (i=0; i < 2; i++)

      {

        printf("\nName: %s", ArrayPointer++);  

      }

}

void main()

{

  int i;

  pNameList = &NameList[0][10];

  Function(pNameList);  //Pointer To The Array Is Passed Through The Function

}

Solution 2::

Code:



char NameList[][10] = { "Father", "Mother"};



void Function(char ArrayPointer[][10])

{

    int i;

    for (i=0; i < 2; i++)

      {

        printf("\nName: %s", ArrayPointer[i]);  

      }

}

void main()

{

  int i;

  Function(NameList);  //Pointer To The Array Is Passed Through The Function

}

Bye the way ! in C write function declaration before main function and also specify return type for better coding practice and professional coding look.

Enjoy....Buddy......:D