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arun12138 6Dec2008 11:32

why this code shows diffferent results

main( )
float a = 15.5 ;
char ch = 'C' ;
printf ( "\n%f %c", a, ch ) ;
printit ( a, ch ) ;
printit ( float sa, char sch )
 printf ( "\n%f %c", sa, sch ) ;

this shows 15.5 C in main printf() and 0.00 in printit() why?

xpi0t0s 6Dec2008 14:20

Re: why this code shows diffferent results
What compiler are you using?
Does it work correctly if you redefine printit to void instead of default-int and place it above main (or prototype it)?

Tried it in Visual Studio 2005 and it wouldn't compile because of the above; I set the return of printit to void and moved it above main and it worked fine.

So I'd guess this is either a compiler bug or a consequence of some of the default behaviour you're relying on here (mainly that when the compiler finds printit in use it assumes its prototype is "int printit()" ).

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