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pointer string
Hello
If I take a string declaration as below: char str[5]="Mike"; than the following statement does NOT produce error str[start] ^= str[end]; If I take a string declaration as below: char *str="Mike"; that the above mentioned statement str[start] ^= str[end]; DOES produce error. So I want to know , that if my string declaration is as in second case (char *str="Mike";) than , how to write XOR statement so that it should not produce error. Thank You |
Re: pointer string
The second case is a pointer to a string CONSTANT.
So you cannot (generally) change it. |
Re: pointer string
Thank you
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Re: pointer string
buddy i tried out ur code
char *str="MIKE"; str[0]^=str[4]; printf(" %s",str); it gives no error... so i dont get it were is ur problem? |
Re: pointer string
micsom, you're probably using a different compiler, which one is it? Modifying a string constant should throw an error, since it's an operation you shouldn't perform.
XOR-ing something with zero DOESN'T modify it, so mabye the compiler's outsmarting the lot of us. Try this: Code:
char *str1="Mike"; |
Re: pointer string
Quote:
my code is... Code:
#include<stdio.h> |
Re: pointer string
Actually i first tried with th given code for which the output was:
Code:
(ikeBut then when I changed str1[3] to str1[4], the problem got solved immediately....cna anyone explain me why?? |
Re: pointer string
Well as I said you shouldn't modify string constants so str1[<anything>]^=<anthing> should throw an error - a compile time error if nothing else.
However if it works, to find out why 'M' xor 'e' produces '(' you'll need to look at an ASCII table and the binary values of those three characters. 'M' xor str1[4] = 'M', since str1[4]=0 (it's the terminating NULL). And as I said above, xor-ing anything with zero has no effect. |
Re: pointer string
Thanks......now I hope I understand the lot....thank you very very much xpi0tos
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