How to pass head address of linked list to a function in C programming

Hi,
Could someone explain how to write a function to access and display head node in a one node linked list only? I am learning linked list of my own and I am stuck there. Can someone explain it urgently? Thank you very much in advance.

I have written following code In Turbo C. Please let me know what is wrong in the code:
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Code:

#include<stdio.h>
#include<conio.h>
#include<malloc.h>
void display(struct node *)
void main()
{
                  struct node
                  {
                                    int x;
                                    struct node *next;
                   };
                  struct node *head,*temp;
                  clrscr();

                 head=NULL;
   
                 temp=(struct node*)malloc(sizeof(struct node*));
                  temp->x=500;
                 temp->next=NULL;

                 head=temp;

                 display(head);   \\this is reall not working. Please can some on explain urgently\\             

                 getch();           
}
void display(struct node *p)
{
                struct node *ptr;
                 ptr=p;

                 printf("%d",ptr->x);  \\whether to declare a local variable x here to print int value in the node?\\
}

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