1. This site uses cookies. By continuing to use this site, you are agreeing to our use of cookies. Learn More.

write a prog to count the no word,space,sentence,vowels,and constants

Discussion in 'C' started by vikas k verma, Nov 9, 2011.

  1. vikas k verma

    vikas k verma New Member

    Joined:
    Nov 9, 2011
    Messages:
    1
    Likes Received:
    0
    Trophy Points:
    0
    Code:
    #include<stdio.h>
    #include<conio.h>
    #include<string.h>
    void main()
    {
    char a[50];
    int i,len=0,word=1,sant=0,space=0,vow=0,cons=0,line=1;
    clrscr();
    printf("plz enter the string\n");
    gets(a);
    /*len=strlen(a);*/
    /* OR */
    for(i=0;a[i]!='\0';i++)
    {
      len++;
    }
    for(i=0;i<=len;i++)
    {
     if(a[i]==' ')
     {
      space++;
     }
     if(a[i]==' '&&(a[i]>='a'||a[i]<='z'))
     {
      word++;
     }
     else if(a[i]=='.')
     {
      sant++;
     }
     else if(a[i]=='a'||a[i]=='e'||a[i]=='i'||a[i]=='o'||a[i]=='u'||a[i]=='A'||a[i]=='E'||a[i]=='I'||a[i]=='O'||a[i]=='U')
     {
      vow++;
     }
     else if(a[i]=='b'||a[i]=='c'||a[i]=='d'||a[i]=='f'||a[i]=='g'||a[i]=='h'||a[i]=='j'||a[i]=='k'||a[i]=='l'||a[i]=='m'||a[i]=='n'||a[i]=='p'||a[i]=='q'||a[i]=='r'||a[i]=='s'||a[i]=='t'||a[i]=='v'||a[i]=='w'||a[i]=='x'||a[i]=='y'||a[i]=='z'||a[i]=='B'||a[i]=='C'||a[i]=='D'||a[i]=='F'||a[i]=='G'||a[i]=='H'||a[i]=='J'||a[i]=='K'||a[i]=='L'||a[i]=='M'||a[i]=='N'||a[i]=='P'||a[i]=='Q'||a[i]=='R'||a[i]=='S'||a[i]=='T'||a[i]=='V'||a[i]=='W'||a[i]=='X'||a[i]=='Y'||a[i]=='Z')
     {
     cons++;
     }
     else if(a[i]=='\n')
     {
     line++;
     }
    }
    printf(" length=%d\n words=%d\n space=%d\n santence=%d\n vowel=%d\n consonent=%d\n",len,word,space,sant,vow,cons);
    printf(" line=%d",line);
    getch();
    }
     
    Last edited by a moderator: Nov 9, 2011
  2. xpi0t0s

    xpi0t0s Mentor

    Joined:
    Aug 6, 2004
    Messages:
    3,012
    Likes Received:
    203
    Trophy Points:
    0
    Occupation:
    Senior Support Engineer
    Location:
    England
    Interesting, could you explain what you think this will do?
    Code:
    if(a[i]==' '&&(a[i]>='a'||a[i]<='z'))
    
     
  3. poornaMoksha

    poornaMoksha New Member

    Joined:
    Jan 29, 2011
    Messages:
    150
    Likes Received:
    33
    Trophy Points:
    0
    Occupation:
    Software developer
    Location:
    India
    Please dont use 'gets()' in your code. It is a handy tool for hackers to intrude into your programs.

    Spare some time and read :
    http://cboard.cprogramming.com/c-programming/25338-why-gets-function-dangerous.html


    Also, as xpi0t0s said, the condition :

    Code:
    if(a[i]==' '&&(a[i]>='a'||a[i]<='z'))
    does not make any sense. '&&' means that both conditions should be true to enter the 'if' block. But how is this possible for a to be equal to space ' ' and some alphabet (a-z) at the same time?
     

Share This Page