# How to have to variable looping at the same time with the same increment?

Discussion in 'C' started by askmewhy25, Mar 5, 2010.

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Here is my problem I can't figure out how to loop two variable at the same
while they increment at the same time with the same increment
I can't explain myself I will just give an example:

Code:
```The increment is 50
T1          T2
300         350
350         400
400         450
450         500
500         550
550         600
600         650
650         700
700         750
750         800
800         850
850         900
900         950
950         1000
```
Here is my program
Code:
```#include <stdio.h>
#include <conio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>

int main(){
int i,j,T;

printf("Input T: ");
scanf("%d",&T);
for(j=300+T;j<=1000;j+=T)
for(i=300;i<=(1000-T);i+=T){
printf("T1 = %d and T2 = %d\n",i,j);
}
getche();
}
```

Last edited: Mar 5, 2010
2. ### karthigayanNew Member

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I checked your code in linux machine.so I have changed few lines.

In your code there is no need to two loops.You can do that using a single loop.

Code:
```#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>

int main(){
int i,j,T;

printf("Input T: ");
scanf("%d",&T);
for(i=300;i<=950;i+=T)
{
j=i+50;
printf("T1 = %d and T2 = %d\n",i,j);
}
}
```

3. ### techgeek.inNew Member

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do this:-
Code:
```#include <stdio.h>
#include <conio.h>

int main(){
int i,j,T;

printf("Input T: ");
scanf("%d",&T);
for(i=300,j=350;i<=1000  && j<=1000 ;i+=T,j+=T)
{
printf("T1 = %d and T2 = %d\n",i,j);
}
getch();
return 0;
}

```

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Thanks techgeek.in but i have another question..:happy: if the user wanted to input numbers with decimal numbers how will i do that??

5. ### virxenNew Member

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Code:
```#include <stdio.h>

int main(){
float T1,T2,end1,increment;
printf("first variable=");
scanf("%f",&T1);
printf("second variable=");
scanf("%f",&T2);
printf("increment for first and second variable=");
scanf("%f",&increment);
printf("end when first variable is>=");
scanf("%f",&end1);
printf("The increment is %f",increment);
printf("\n     T1              T2\n");
while(T1<end1){
T1+=increment;
T2+=increment;
printf("%10.3f      %10.3f\n",T1,T2);
}
getchar(); getchar();
}

```
with this code you can have T1,T2 and increment as demical numbers

Last edited: Mar 5, 2010
6. ### techgeek.inNew Member

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Not an alien!! for sure
u can try this:-
Code:
```#include <stdio.h>
#include <conio.h>

int main(){
float i,j,T;

printf("Input T: ");
scanf("%f",&T);
for(i=300.0,j=350.0;i<=1000.0  && j<=1000.0 ;i+=T,j+=T)
{
printf("T1 = %f and T2 = %f\n",i,j);
}
getch();
return 0;
}
```

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Now I upgraded the program.. thanks to all your help!! but i have a last question
how can I set the range or the stopper to T2 to 1000K because the table of the ideal
gas is for only 300K to 1000K so beyond that range in not applicable..

Code:
```//This program generates a table for the specific internal energy
//and the specific enthalpy of Methane from 300K to 1000K using the
//specific heat variations listed on Table A.21

#include <stdio.h>
#include <conio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>

int main(){
int QA;
float T1=300,T2,end1,inc;
double a=3.826,b=-3.979,c=24.558,d=-22.733,e=6.963;
double A,B,C,D,E,H,U,R=8.3143,M=16.04,i=10;
char error[128];

do{
do{
system("cls");
printf("Enter the Increment in Temperature: ");
scanf("%s",&error);
inc=atof(error);
if(inc<=0){
system("cls");
printf("Please press the spacebar to continue!!");
getche();
}
}while(inc<=0);
T2=T1+inc;
end1=1000-inc;
printf("The increment is %.3f\n\n",inc);
printf("\nInitial Temperature\tFinal Temperature\tEnthalpy\tInternal Energy\n");
while(T1<=end1){
T1+=inc;
T2+=inc;
A=a*(T2-T1);
B=(1/pow(i,3))*(b/2)*(pow(T2,2)-pow(T1,2));
C=(1/pow(i,6))*(c/3)*(pow(T2,3)-pow(T1,3));
D=(1/pow(i,9))*(d/4)*(pow(T2,4)-pow(T1,4));
E=(1/pow(i,12))*(e/5)*(pow(T2,5)-pow(T1,5));
H=(R/M)*(A+B+C+D+E);
U=(R/M)*((A+B+C+D+E)-(T2-T1));
printf("%10.3f K\t\t%10.3f K\t\t%.3f kJ/kg\t%.3f kJ/kg\n",T1,T2,H,U);
}
do{//This used to ask the user if s/he wants to repeat the evaluation
printf("\n\nDo you want to repeat the computation or Quit?\n");
printf("[1] Yes\n");
printf("[2] Quit\n");
scanf("%s",&error);
QA=atoi(error);
switch(QA){
case 1:
break;
exit(1);
break;
default://The program redirects invalid inputs to this part
system("cls");
printf("Please press the spacebar to continue!!");
getche();
break;
}
}while(QA>2||QA<1);
}while(QA==1);
getche();
}
```

8. ### techgeek.inNew Member

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see this:-
Code:
```//This program generates a table for the specific internal energy
//and the specific enthalpy of Methane from 300K to 1000K using the
//specific heat variations listed on Table A.21

#include <stdio.h>
#include <conio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>

int main(){
int QA;
float T1=300,T2,end1,inc;
double a=3.826,b=-3.979,c=24.558,d=-22.733,e=6.963;
double A,B,C,D,E,H,U,R=8.3143,M=16.04,i=10;
char error[128];

do{
do{
system("cls");
printf("Enter the Increment in Temperature: ");
scanf("%s",&error);
inc=atof(error);
if(inc<=0){
system("cls");
printf("Please press the spacebar to continue!!");
getche();
}
}while(inc<=0);
T2=T1+inc;
end1=1000-inc;
printf("The increment is %.3f\n\n",inc);
printf("\nInitial Temperature\tFinal Temperature\tEnthalpy\tInternal Energy\n");
while(T1<=end1){
T1+=inc;
T2+=inc;
A=a*(T2-T1);
B=(1/pow(i,3))*(b/2)*(pow(T2,2)-pow(T1,2));
C=(1/pow(i,6))*(c/3)*(pow(T2,3)-pow(T1,3));
D=(1/pow(i,9))*(d/4)*(pow(T2,4)-pow(T1,4));
E=(1/pow(i,12))*(e/5)*(pow(T2,5)-pow(T1,5));
H=(R/M)*(A+B+C+D+E);
U=(R/M)*((A+B+C+D+E)-(T2-T1));
printf("%10.3f K\t\t%10.3f K\t\t%.3f kJ/kg\t%.3f kJ/kg\n",T1,T2,H,U);
}
do{//This used to ask the user if s/he wants to repeat the evaluation
printf("\n\nDo you want to repeat the computation or Quit?\n");
printf("[1] Yes\n");
printf("[2] Quit\n");
scanf("%s",&error);
QA=atoi(error);
switch(QA){
case 1:
break;
exit(1);
break;
default://The program redirects invalid inputs to this part
system("cls");
printf("Please press the spacebar to continue!!");
getche();
break;
}
}while(QA>2||QA<1);
}while(QA==1 && T2<=1000);
getche();
}

```

9. ### virxenNew Member

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correct the above code like this

Code:
```.......................
switch(QA){
case 1:
break;
exit(1);
......................
```
Code:
```}while(QA>2||QA<1);
}while(QA==1 && T2<[COLOR=Red]=[/COLOR]1000); [COLOR=Red]//i am not sure but i think you must remove =   [/COLOR]
getche();
}

```

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I figured it out already..hehe the only thing that is needed to be change is this

Code:
```  T1=300-inc;
T2=300;
end1=1000-inc;
```
Program
Code:
```//This program generates a table for the specific internal energy
//and the specific enthalpy of Methane from 300K to 1000K using the
//specific heat variations listed on Table A.21

#include <stdio.h>
#include <conio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>

int main(){
int QA;
float T1=300,T2,end1,inc;
double a=3.826,b=-3.979,c=24.558,d=-22.733,e=6.963;
double A,B,C,D,E,H,U,R=8.3143,M=16.04,i=10;
char error[128];

do{
do{
system("cls");
printf("Enter the Increment in Temperature: ");
scanf("%s",&error);
inc=atof(error);
if(inc<=0){
system("cls");
printf("Please press the spacebar to continue!!");
getche();
}
}while(inc<=0);
T2=T1+inc;
end1=1000-inc;
printf("The increment is %.3f\n\n",inc);
printf("\nInitial Temperature\tFinal Temperature\tEnthalpy\tInternal Energy\n");
while(T1<=end1){
T1+=inc;
T2+=inc;
A=a*(T2-T1);
B=(1/pow(i,3))*(b/2)*(pow(T2,2)-pow(T1,2));
C=(1/pow(i,6))*(c/3)*(pow(T2,3)-pow(T1,3));
D=(1/pow(i,9))*(d/4)*(pow(T2,4)-pow(T1,4));
E=(1/pow(i,12))*(e/5)*(pow(T2,5)-pow(T1,5));
H=(R/M)*(A+B+C+D+E);
U=(R/M)*((A+B+C+D+E)-(T2-T1));
printf("%10.3f K\t\t%10.3f K\t\t%.3f kJ/kg\t%.3f kJ/kg\n",T1,T2,H,U);
}
do{//This used to ask the user if s/he wants to repeat the evaluation
printf("\n\nDo you want to repeat the computation or Quit?\n");
printf("[1] Yes\n");
printf("[2] Quit\n");
scanf("%s",&error);
QA=atoi(error);
switch(QA){
case 1:
break;
exit(1);
break;
default://The program redirects invalid inputs to this part
system("cls");