Hello i have created a simple program but not finding the solution to understand the Output of the code. Please any one Solve this code and output:----- Help!!!!!! { int a,b,c,d; printf("%d%d%d%d",3,3+2,c,a+b*c-d); getch(); }
I am not surprised, you don't understand your output. To get proper output first you should initialize your variables with some values.
when u dont initialize ur variables how can u expect the appropriate output? if u want u initialize den try the below statements before ur printf statement: printf("enter the valuse of a,b,c,d); scanf("%d,%d,%d,%d",&a,&b,&c.&d); now u cn get ur desired ans :happy:
let me change your code a little bit in order to explain better Code: #include <stdio.h> int main(){ [COLOR=Red]int a=1,b=2,c=3,d=4;[/COLOR] printf("%d%d%d%d",3,3+2,c,a+b*c-d); getchar(); return 0; } in your printf you have a string inside the quotes "%d%d%d%d " and a series of numbers and variables separated by comma (,) when printf finds inside the string this--->%d it means replace it with an integer value the first %d is replaced by the first integer after the string so we have %d-->3 %d-->3+2 --->5 %d-->c ---->in my code is 3 %d-->a+b*c-d --> in my code is 1+2*3-4=3 so what it prints now? 3533