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Problem to understand the O/p of the CODE

Discussion in 'C' started by Mohit_Malhotra, Nov 20, 2010.

  1. Mohit_Malhotra

    Mohit_Malhotra New Member

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    Hello i have created a simple program but not finding the solution to understand the Output of the code.


    Please any one Solve this code and output:----- Help!!!!!!
    {
    int a,b,c,d;
    printf("%d%d%d%d",3,3+2,c,a+b*c-d);
    getch();
    }
     
  2. ihatec

    ihatec New Member

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    I am not surprised, you don't understand your output. To get proper output first you should initialize your variables with some values.
     
  3. animadhu

    animadhu New Member

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    when u dont initialize ur variables how can u expect the appropriate output?
    if u want u initialize den try the below statements before ur printf statement:
    printf("enter the valuse of a,b,c,d);
    scanf("%d,%d,%d,%d",&a,&b,&c.&d);
    now u cn get ur desired ans :happy:
     
  4. virxen

    virxen New Member

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    let me change your code a little bit in order to explain better

    Code:
    #include <stdio.h>
    
    int main(){
    [COLOR=Red]int a=1,b=2,c=3,d=4;[/COLOR]
    printf("%d%d%d%d",3,3+2,c,a+b*c-d);
    getchar();
    return 0;
    }
    
    in your printf you have a string inside the quotes "%d%d%d%d "
    and a series of numbers and variables separated by comma (,)

    when printf finds inside the string this--->%d it means replace it with an integer value
    the first %d is replaced by the first integer after the string
    so we have
    %d-->3
    %d-->3+2 --->5
    %d-->c ---->in my code is 3
    %d-->a+b*c-d --> in my code is 1+2*3-4=3

    so what it prints now?
    3533
     
    shabbir likes this.

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