![]() |
|
|||||||
![]() |
|
|
|
Bookmarks | Thread Tools | Search this Thread | Display Modes |
|
|
#1 |
|
Go4Expert Member
Join Date: Jul 2007
Posts: 14
Thanks: 0
Thanked 0 Times in 0 Posts
Rep Power: 0 ![]() |
Why is it throwing "number format exception" ?Code:
//WAP That convert integer value into binary,octal and hexdecimal.
import java.io.*;
class numconv
{
public static void main(String s[])throws IOException
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
char ch='y';
int opt,num;
String bin,oct,hex;
do
{
System.out.println("******* 1: Convert number to Binary format ********");
System.out.println("******* 2: Convert number to Octal format *********");
System.out.println("******* 3: Convert number to Hexadecimal format ***");
System.out.print("\n\n Enter Option :");
opt=Integer.parseInt(br.readLine());
switch(opt)
{
case 1:
System.out.print("\n\nEnter Number :");
num=Integer.parseInt(br.readLine());
bin=Integer.toBinaryString(num);
System.out.println("\nBinary equivalent of "+num+" is "+bin);
break;
case 2:
System.out.print("\n\nEnter Number :");
num=Integer.parseInt(br.readLine());
oct=Integer.toOctalString(num);
System.out.println("\nOctal equivalent of "+num+" is "+oct);
break;
case 3:
System.out.print("\n\nEnter Number :");
num=Integer.parseInt(br.readLine());
hex=Integer.toHexString(num);
System.out.println("\nHexadecimal equivalent of "+num+" is "+hex);
break;
}
System.out.print("\n\n Enter your choice(y/n) :");
ch=(char)br.read();
}while(ch!='n');
}
}
Here is the output ******* 1: Convert number to Binary format ******** ******* 2: Convert number to Octal format ********* ******* 3: Convert number to Hexadecimal format *** Enter Option :1 Enter Number :5643 Binary equivalent of 5643 is 1011000001011 Enter your choice(y/n) :y Here, when i am entering 'y' or value other than 'n' it is throwing exception. ******* 1: Convert number to Binary format ******** ******* 2: Convert number to Octal format ********* ******* 3: Convert number to Hexadecimal format *** Enter Option :Exception in thread "main" java.lang.NumberFormatException: For i nput string: "" at java.lang.NumberFormatException.forInputString(Num berFormatException. java:48) at java.lang.Integer.parseInt(Integer.java:447) at java.lang.Integer.parseInt(Integer.java:476) at numconv.main(numconv.java:24) Last edited by shabbir; 01-22-2008 at 05:38 PM. Reason: Code block |
|
|
|
|
|
#2 |
|
Banned
Join Date: Nov 2007
Posts: 3
Thanks: 0
Thanked 0 Times in 0 Posts
Rep Power: 0 ![]() |
Re: Why is it throwing "number format exception" ?
you type a letter "y", and then you type a line return read() just reads one character ("y") the line return is still in the stream then when readLine() is called, it reads until it encounters a line return, which is the first character it encounters so it returns an empty line Integer.parseInt() cannot parse an empty string |
|
|
|
|
|
#3 |
|
Team Leader
![]() |
Re: Why is it throwing "number format exception" ?
change br.readLine() to br.read();
__________________
Vote for the Most Entertaining Member of 2008 To err is human,to detect is divine! |
|
|
|
|
|
#4 |
|
Ambitious contributor
Join Date: Feb 2008
Posts: 104
Thanks: 0
Thanked 0 Times in 0 Posts
Rep Power: 2 ![]() |
Re: Why is it throwing "number format exception" ?
hi can you please give some explanation for your code i needed some help
|
|
|
|
![]() |
|
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
| Display Modes | |
| Bookmarks | |
|
|
|
|||||||||||||||||||||||||||