I've got a question about using the 6800 emulator to create a program that multiplies 2 arbitary 8 bit numbers to generate an 8 bit number. now, i've attempted it, this is what i've done in the quote below.
eleven .equ 11
fourteen .equ 14
P .equ 0
PnB ldaa #fourteen
shiftP ldaa #P
Okay, the teacher went through it in class, and he showed how it was shifting each step, eg:
C P A
0 0000 1011
N=1 0 1110 1011 (LSB = 1, so P+B=P)
0111 0101 (Shift Bits Right)
N=2 1 0101 0101 (LSB = 1, so P+B=P)
0 1010 1010 (Shift Bits Right)
So at first i couldn't do it, but i attempted it and i did that in the quote up the top. I don't think it's correct though cause when i look at it, it just doesn't look right. I was wondering if anyone could give me some pointers on what im doing wrong so I at least know how to fix it.