Hi,

I've got a question about using the 6800 emulator to create a program that multiplies 2 arbitary 8 bit numbers to generate an 8 bit number. now, i've attempted it, this is what i've done in the quote below.

Quote:

eleven .equ 11

fourteen .equ 14

P .equ 0

ldab #4

loop cba

ldaa #eleven

tst 0,x

jmp PnB

PnB ldaa #fourteen

adaa #P

jmp plus

plus asla

staa P

jmp shiftP

shiftP ldaa #P

asla

decb

tstb

bne loop

.org $0120

Okay, the teacher went through it in class, and he showed how it was shifting each step, eg:

C P A

0 0000 1011

N=1 0 1110 1011 (LSB = 1, so P+B=P)

0111 0101 (Shift Bits Right)

N=2 1 0101 0101 (LSB = 1, so P+B=P)

0 1010 1010 (Shift Bits Right)

So at first i couldn't do it, but i attempted it and i did that in the quote up the top. I don't think it's correct though cause when i look at it, it just doesn't look right. I was wondering if anyone could give me some pointers on what im doing wrong so I at least know how to fix it.

Thanks,

Ashley