[bpeg110]

I will need to check how many employees are on the old roster. For each employee, I will need to check to see if the NEW employee’s name should be printed before it. If so, print the new employee’s name, followed by the old employee. Otherwise, simply print the old employee’s name. This should repeat until all the names (new and old) have been printed to the new roster.

This is what I have so far:

#include <stdio.h>
#include <string.h>

struct record{
    char fname[20];
    char lname[20];
};

int namecmp (struct record eA, struct record eB);

int main() {
    FILE *ifp = fopen("input.txt", "r");
    FILE *ofp = fopen("roster.txt", "w");
    int num_people, i, flag=0;
    struct record new_employee, temp_employee;
	

    //-Ask the user for the first and last names of the new employee
	printf("What is the first name of the new employee?\n");
	scanf("%s", new_employee.fname);
	
	printf("What is the last name of the new employee?\n");
	scanf("%s",  new_employee.lname);
    
	//-Get the number of employees on the roster from the input file
	fscanf(ifp, "%d", &num_people);
	

	for(i = 0; i < num_people; i++){
	    fscanf(ifp, "%s", temp_employee.lname);
	    fscanf(ifp, "%s", temp_employee.fname);
	
		namecmp(temp_employee, new_employee);
	}	
		
	
	//-Set up a loop for the number of employees
    //-Each time you should do the following:
    //--Read in a name from the input file
    //--Use the provided namecmp function to see if the
    //      new employee should be printed first
    //--Print the old employee to the output file

    //-If the new employee was never printed, print at the end of the file

    fclose(ifp);
    fclose(ofp);

    return 0;
}

/* Pre-Conditions: This function takes in two structures of type record.
 * These are labeled eA and eB for employee A and employee B, respectively.
 * Post-Conditions: This function compares the names of the two
 * employee to see which should come first lexicographically.
 * The function returns -1 if eA comes first, 1 if eB comes first,
 * and 0 if the employees have the same name.
 */
int namecmp (struct record eA, struct record eB) {
    if (strcmp(eA.lname, eB.lname) < 0)
        return -1;
    else if (strcmp(eA.lname, eB.lname) > 0)
        return 1;
    else {
        if (strcmp(eA.fname, eB.fname) < 0)
            return -1;
        else if (strcmp(eA.fname, eB.fname) > 0)
            return 1;
        else
            return 0;
    }
}