[jimmy]

i have some doubts regarding bash scripting ,

1) i need to display permission of a given file in the following format :

Owner :

Read
Write

Group :

Read
Write

Others :

Read
Execute

so i wrote this code :

echo -n "Enter Filename : " ; read fname ;
 
# check if file exists
if [ -e $fname ]
then
     
#display fap for owner 
 
    echo "Owner"
 
    ls -l $fname|awk  '{print $1 }' |tee temp | cut -c2-4
 
#display fap for group users
    
    echo "Group"
 
    cat temp | cut -c5-7
 
#display fap for other users
 
    echo "Other"
    
    cat temp | cut -c8-10
else
    echo "FIle does not exist"
fi

the output i get is :

Owner 
rwx
Group
r-x
Others
r--

i want to print the words "Read" "Write" "Execute" instead of 'rwx'. If it were only for the owner , i could use the test command and -r, -w, -x options but that doesnt work for Group and Other users, how do i do that ?



2) i need to delete all duplicate files ,

so i wrote this,

find .  -maxdepth 1 -type f  -print0 | xargs -0 md5sum | sort | uniq -w 32 -c  | awk '{ print $1, $3 }' | find -ok rm {} \;

but it is incomplete, it deletes all files , which means even the original file would be lost.


3) Need to check if any user has logged-in more than once in different terminal, then display the no. of instances of that login.

Sorry , no code tried for this one. I dont know where to start from.


4) And im trying to display files that have been created today ,

as i understand , unix keeps the track of files by the modification date and doesn't store the creation date, so how do i accomplish this task.


i have tried my best to solve these doubts by reading numerous tutorials . but still couldn't find my answers. Please help.

Thanks for reading the post.

[Peter_APIIT]

You are the best