[PEANUTS]

The idea:
Using looping methods and the IF constrcut to print the numbers between 1 and 10 along with an idications of whether each is even or odd. Like this

1 is odd
2 is even
3 is odd

Using C

My attempt:

/* Name:

Cameron Owen
CIC Y1 G1
Software Development
Mathmatics

*/

#include <stdio.h>
void main (void)

{
int iCount;                     //decalered integar variable
iCount=1;					//assigning 1 to iCount
clrscr();
				do{
				printf("%d",iCount);

					if(iCount, "%/2==0");
					printf ("EVEN\n");
					else
					printf ("ODD\n");

					iCount++;
				  }while(iCount<11);
getch();
}

i understand the basic idea for C but require further assisance. This only gives one error. Else is misplaced.
I know there are other ways to do this without the need to use a maths division but that would only work for the numbers i choose.

My idea is, if a number is divisable by 2 and gives a remainder 0. Then its even
If a number is divisable by 2 and gives a remiander 1. It is odd


Many thanks if you help me on this,

Cameron

[shabbir]

You have posted it as an Article under the Article / Source code section. I have moved it to the Queries and Discussion forum.

Also please use the bbcode for the code snippets you put in.

[shabbir]

Just replace the dowhile loop with the following

do{
	printf("%d",iCount);
	
	if(iCount%2==0)
		printf ("EVEN\n");
	else
		printf ("ODD\n");
	
	iCount++;
}while(iCount<11);