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Pointers and Structures

Discussion in 'C' started by gk123987, Oct 10, 2008.

  1. gk123987

    gk123987 New Member

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    I have a complex query,

    I have a structure some thing like this,

    typedef struct mod_Definition_T_Tag
    {
    int x;
    char y;
    float p;
    } mod_Definition_T;

    if in the code if the declaration is made as follows:

    typedef mod_Definition_T *(*create_func_t)(const char *config_str);

    what does this indicate or how do we put them in plain english statement ?
     
  2. gk123987

    gk123987 New Member

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    Is there any way by which we can access a function using the functions address alone?
     
  3. oogabooga

    oogabooga New Member

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    typedef mod_Definition_T *(*create_func_t)(const char *config_str);

    This declares a function pointer type called "create_func_t".
    It takes a const char* as an argument and returns a mod_Definition_T *.

    A simpler example of a function pointer declaration is:

    typedef int (*func) (int);

    This declares a function pointer type called func which takes an int
    and returns an int. You define function pointer variables from it like this:

    func a, b, c; // a, b, and c are function pointers of type func.

    And you can use the function pointers just like regular function names:

    int x = a(5);

    Your original example might be used something like this:

    create_func_t cft;
    mod_Definition_T *mdt = cft( "abcdefg");


    A function name is an address (i.e., a pointer).
     
    shabbir likes this.

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