Pointer to memory address

Hi,
I have a small problem. Following a pointer to point to a particular segment: offset (for example 0041Ch)
How can I now put a pointer to this address?

 

But once the trial here is not whether the white Abder:

Code:

char* pointer; 
Pointer = 0x0041;

 

Segment and offset the smell of DOS programming, so all that follows is not a standard C + +, but Borland / Turbo C + + specific (DJGPP perhaps?)

Code:

# Include <dos.h> 
char Far * my_far_pointer MK_FP = (0, 0x41C) / * make pointer Far 0000:041 c * /

 

Once I add a variable I can no prob to access the address range. Can someone tell me why it does not go without a variable?

Achso, I get the following error: expression must be a pointer or a zero constant.

So far, no solution works ... : (

who has other solutions ... just tell me

 

the relevant code would still be useful ...

 

Well, I would say, because the memory area you may not
belongs.

 

Well, my current program does not have anything with the code you need to do now. I would just say exactly, I always read the values of exactly this location. With pure assembler can I do that ... But everything must go without asm. Can I ever passed from one hand to the pointer location?

 

Yes, but you can neither read nor write it because you like the memory
area is not heard.

 

Hi,

I have such a result that works on Linux, should be enumerated under other systems.

Code:

int mem_addr = 0x0041; 
int * ptr_of_int; 
long * ptr_of_long; 
char * ptr_of_char; 

ptr_of_int = (int *) mem_addr; 

ptr_of_long = (long *) mem_addr; 

ptr_of_char = (char *) mem_addr; 

 

I would say that depends entirely on the OS