Code: #include <stdio.h> #include <conio.h> int A(int x) { x++; return(x+1); } int B(int y,int z) { int t, i; t=1; for(i=1;i<=y;i++) t*=i; for(i=1;i<=z; i++) t+=i; return(t); } main() { int m,n,x; m=2; n=4; printf("%d\n", B(m,n)+B(n,m)); printf("%d\n",A(B(m,n))); m=3; n=A(n); m=B(n,m); printf("%d\n%d\n%d", n,m,B(n,m)); getch(); return 0; } by simulation, i am able to get the values for the first two printf. and on the 3rd printf,how come m=726 and B(n,m)=264261? i run the code because i do not have the idea how to simulate to get the values for m and B(n,m) please! somebody explain it.this will help me pass my exam. Nested Loop Simulation

The first printfs call by value so they don't change n or m when they return. After that, you've assigned both n and m values Code: m=3; n=A(n); m=B(n,m); n = A(4) = 6 m = B(6, 3) = 726 Code: printf("%d\n%d\n%d", n,m,B(n,m)); here your parameter list to printf looks like 6, 726, B(6, 726) from the B definition Code: B(6, 726) t=1 for(i=1;i<=6;++i) 1 x 1 = 1 1 x 2 = 2 2 x 3 = 6 6 x 4 = 24 24 x 5 = 120 120 x 6 = 720 t now equals 720 for(i=1; i<=726; ++i) 720 + 1 = 721 721 + 2 = 723 723 + 3 = 726 ... I don't know the value of t with each iteration, but it's obvious that t will grow a bit