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matrix challenge

Discussion in 'C' started by chai123, Oct 4, 2012.

  1. chai123

    chai123 New Member

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    Okay so Ive made a program that only asks a user for the # of columns of a matrix and then determines the rows of the matrix and displays it. The problem is if the user for example for a 2 by 2 matrix enters only 3 values then the program doesnt work. I want the program to show 2 rows for 3 values and then maybe put 0 as the fourth value. Please help
    Code:
    #include<stdio.h>
    #include<stdlib.h>
    
    int  main()
    {
      int m,x, n, c = 0, d,k, matrix[10][10], transpose[10][10], product[10][10];
    
      printf("Enter the number of columns of matrix ");
      scanf("%d",&m);
      if(m<=0){
        printf("You entered a invalid value.");
        exit(0);
      }
      else{
        printf("Enter the elements of matrix \n");
    
        for( c = 0 ; c < 10 ; c++ )
          {
            for( d = 0 ; d < m ; d++ )
              {
                scanf("%d",&matrix[c][d]);
                if (matrix[c][d] == 99) // 'x' is character variable I declared to use as a break
               break;
                // c = c+1;
    
              }
            if (matrix[c][d] == 99)
              break;
          }
      }
    
      printf("\nHere is your matrix:\n");
      int i;
    
      for(i=0;i<c;i++)
        {
          for(d=0;d<m;d++)
            {
              /* if( matrix[c][d] <0){
                printf("Not possible");
                exit(0);
     }
              else{*/
    
              printf("%3d ",matrix[i][d]);
            }
          printf("\n");
        }
     

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