Code: C++
/*dis is a love meter program in c
it is based on "FLAMES"
where
F-FLAMES
L-LOVE
A-ADORABLE
M-MARRIAGE
E-ENEMITY
S-SISTER
so just enter ur first name
n den ur partner's name
and see the result*/
#include"stdio.h"
#include"conio.h"
#include"string.h"
void main()
{
printf("THIS IS A RELATION METER WHICH SHOWS YOUR RELATION WID UR PARTNER\n");
printf("\n");
char yn[100],pn[100];
char a[6]={'f','l','a','m','e','s'};
int i,j,p=0,len=0,len1=0,t,t1,nl,count,sz=6,nl1;
printf("enter your name:");
gets(yn);
printf("\nenter ur love partner's name:");
gets(pn);
int l=strlen(yn);
int l1=strlen(pn);
for(i=0;i<l;i++)
{
t=yn[i];
for(j=0;j<l1;j++)
{
t1=pn[j];
if(t==t1)
{
t=0;
yn[i]=0;
pn[j]=0;
}
}
}
t=0;t1=0;
for(int k=0;k<l;k++)
{
t=yn[k];
if(t!=0)
len++;
}
for(int k1=0;k1<l1;k1++)
{
t1=pn[k1];
if(t1!=0)
len1++;
}
nl=len+len1;
for(i=1;i<=6;i++)
{
nl1=nl;
while(nl1>=1)
{
if(p>(sz-1))
{
p=0;
p++;
}
else
p++;
nl1--;
}
p--;
for(k=p+1;k<=(sz-1);k++)
a[k-1]=a[k];
sz--;
}
printf("\n");
printf("YOUR RELATION WID UR PARTNER IS:");
printf("\n");
if(a[sz]=='f')
printf("you and your partner are friends");
else if(a[sz]=='l')
printf(" you love your partner");
else if(a[sz]=='a')
printf("you adore ur partner");
else if(a[sz]=='m')
printf("you will marry your partner");
else if(a[sz]=='e')
printf("there is a relation of enemity");
else if(a[sz]=='s')
printf("your partner is ur sister");
getch();
}

