hello guys
this is my first post in here, I hope you will help me guys
I tried many time but I couldn't get the required pattern
write a c program to generate the
pattern shown using nested for loop
1
01
101
0101
and
0
12
345
6789
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Go4Expert Member
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| 1Apr2010,16:51 | #2 |
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I think this is your home work . Try by your own . If you struck any where then post here .
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Ambitious contributor
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| 1Apr2010,17:21 | #3 |
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Take it step by step try to find some 'pattern' that is there in the output.Try to from a logic on how you could print that than put something over here.Its not that difficult but try yourself.
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Pro contributor
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| 2Apr2010,02:39 | #4 |
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this will give you the opposite from what you want in 1)
do the rest by yourself (hint:you must add 1 char and 1 number in order to work as you want...but where?) Code:
#include <stdio.h>
int main(){
for (int i=0;i<4;i++){
printf("\n");
for (int j=0;j<(i+1);j++)
printf("%d",(i+j)%2);
}
getchar();
return 0;
}
output --------- 0 10 010 1010 with this try and 2)
the white soul
like this
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Newbie Member
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| 4Apr2010,08:58 | #5 |
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Thank you virxen so much
I tried the second but I couldn't get the right answer Code:
#include <stdio.h>
int main(){
for (int i=0;i<4;i++){
printf("\n");
for (int j=0;j<(i+1);j++)
printf("%d",(i+j+1));
}
getchar();
return 0;
}
1 23 345 567 instead of getting 1 23 345 6789 can anyone help me to correct my answer |
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Newbie Member
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| 4Apr2010,09:01 | #6 |
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sorry this is the code
Code:
#include <stdio.h>
int main(){
for (int i=0;i<4;i++){
printf("\n");
for (int j=0;j<(i+1);j++)
printf("%d",(i+j));
}
getchar();
return 0;
}
and the output was 0 12 234 3456 instead of getting 0 12 345 6789 what's wrong in the code so I can get the right answer |
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Mentor
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| 4Apr2010,21:08 | #7 |
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Your code displays on each line values from i (which increases by 1 each new line) to i+j. But you want each line to begin with the last number displayed, plus one.
So how about a counter that just increases each time you print something? Then print the counter instead of trying to calculate something from i and j. |
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Pro contributor
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| 5Apr2010,01:25 | #8 |
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Because you tried to code i will give you the answer for a,b.
Code:
#include <stdio.h>
int main(){
for (int i=0;i<4;i++){
printf("\n");
for (int j=0;j<(i+1);j++)
printf("%d",(i+j+1)%2);
}
getchar();
int count=0;
for (int i=0;i<4;i++){
printf("\n");
for (int j=0;j<(i+1);j++)
printf("%d",count++);
}
getchar();
return 0;
}
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