Quote:
Originally Posted by xpi0t0s View Post
Don't forget that x++ means POSTincrement and ++x means PREincrement. That means before and after, and is usually before or after some execution point. So the equation in some senses (but definitely not all) is equivalent to:
Code:
--y;
z = x - y * b / a;
x++;
This should be a lot easier to evaluate. First y is decremented to -11.
Then z=5 - -11 * 2 / 4
=5 - -22/4
=5 - -5
=5 + 5
=10.

Then x is incremented.
Thank u sir...