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I don't know if a query can be constructed that will return the results you want.
It's a fairly easy problem to solve using some kind of procedural solution; for each node, work out the number of children, recursively (or iteratively) until you have a final solution: 102 (say) has 2 plus the number of children 104 and 105 have; 104 has 2+(107 and 108's children), and so on until all outstanding "N's children" have been resolved.
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