[munkyeetr]

Hi everyone,

When I pass any of the following (-help, help, ?, /?) to this program, I expect it execute the PrintUsage() function, but it doesn't.

I have tested the value of argv[1] before the switch statement, and it showed the correct value, but when it gets to case 2's if/else statement it seems to

return false on the if.

Can anyone tell me what I am doing wrong?

#include <stdio.h>
#include <stdlib.h>

void PrintUsage(void);

int main(int argc, char* argv[]) {

/* holds the sum */
    double dAnswer = 0.0;

/* parse input */
    switch(argc) {

    /* no input parameters */
	    case 1:
	        PrintUsage();
	        break;

    /* only 1 parameter passed; return it */
	    case 2:
		if ((argv[1]=="--help") || (argv[1]=="help") || (argv[1]=="?") || argv[1]=="/?") {
			PrintUsage();
		}
		else {
	        	printf("%.2f\n", atof(argv[1]));
		}
            	
		break;

    /* multiple parameters passed; calculate the sum */
	    default: {
        /* a counter */
	        int iCount = 0;
        /* cycle through input, summing the values */
	        for (iCount = 1; iCount < argc; iCount++) {
	            dAnswer += atof(argv[iCount]);
	        }
        /* print sum to the screen */
	        printf("%.2f\n", dAnswer);
	    }
	}
/* end program */
    return 0;
}

void PrintUsage(void) {
    /* code removed to conserve space */
}