Quote:
Originally Posted by zemzela View Post
This code works, but does not work for this example:

string1 = " rry"
string2 = " yoh"

result is string3 =" rryoh"

The result should be ryoh, not rryoh. This code does not check different letters from first string, just for second.

Can you help me how to solve that?
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Hi Zemzela
I am having difficulty in accessing this forum to edit. Here as below I have my own version of the program. I have been accused of bing a mug. I don't mind it. I believe in making things easy for beginners. When I was a beginner, I luckly had and read many well written programs of other programmers. I hope that you get it too.
Best regards
Chong

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Code:
#include <iostream.h>
#include <string>
using namespace std;
void Union(string &a,string &b);
int main()
{
 string s1 = "122347", s2 = "44567",s3="";
 cout << "First string: "<<s1.c_str()<<'\n';
 cout << "Second string: " << s2.c_str() <<'\n';
 Union(s1,s3);
 Union(s2,s3);
 cout << "Final string: " << s3.c_str() << '\n';
 return 0;
}//main
void Union(string &s2,string &s3)
{
 for (int i=0;i<s2.size();i++){
  char c = s2[i];
  bool is_c_in_s3 =false;
  for (int j=0;j<s3.size();j++){
   if (c==s3[j]){
    is_c_in_s3 = true;
    break;
   }
  }//for
  if (!is_c_in_s3) s3+=c;
 }//for
}

Last edited by shabbir; 18Feb2012 at 13:56.. Reason: Code blocks