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Salem

Because a should be an array of pointers, not an array of arrays.

Code:

char *a[] = { "sample.sh", "one", "two", "three", NULL };

Salem Ambitious contributor
26Nov2007,17:23
	Because a should be an array of pointers, not an array of arrays. Code: char *a[] = { "sample.sh", "one", "two", "three", NULL };