Decimal to Hex

Discussion in 'C' started by bmsangati, Jun 13, 2012.

1. bmsangatiNew Member

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1. //Decimal to Hex value
2. main()
3. {
4. char hex[16]={"0123456789ABCDEF"};
5. int num,i=0,j;
6. char result[];
7. printf("Enter the Decimal No.\n");
8. scanf("%d",&num);
9. while(num)
10. {
11. result=hex[num%16];
[*] num=num=num/16;
[*] i++;
[*] }
[*] printf("Given num of the hex value is:");
[*] for(j=i-1;j>=0;j--)
[*] printf("%c",result[j]);
[*] getch();
[*] return 0;
[*] }

2. bmsangatiNew Member

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:-(

3. pein87New Member

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I was going to code one for you but I found one online. Source

Code:
```string toHexadecimal(int num)
{
int dividend, remain;
string result = "";
string hexArray[16];
hexArray[0] = "0";
hexArray[1] = "1";
hexArray[2] = "2";
hexArray[3] = "3";
hexArray[4] = "4";
hexArray[5] = "5";
hexArray[6] = "6";
hexArray[7] = "7";
hexArray[8] = "8";
hexArray[9] = "9";
hexArray[10] = "a";
hexArray[11] = "b";
hexArray[12] = "c";
hexArray[13] = "d";
hexArray[14] = "e";
hexArray[15] = "f";
dividend = (int)num/16;
remain = num%16;
result = hexArray[remain];
while (dividend != 0)
{
remain = dividend%16;
dividend = (int)dividend/16;
result = hexArray[remain]+result;
}
return result;
}```
It's not meant to be a complete copy paste method but it is meant to show you what you were doing wrong. You made an array with 16 items but only assigned it one value. Each character needs to be a separate item in the array for this to work.

Last edited: Jun 13, 2012