1. This site uses cookies. By continuing to use this site, you are agreeing to our use of cookies. Learn More.

Customer Billing System Correction on Code in C language and not C++

Discussion in 'C' started by Mo Sharif, Nov 30, 2011.

  1. Mo Sharif

    Mo Sharif New Member

    Joined:
    Nov 28, 2011
    Messages:
    1
    Likes Received:
    0
    Trophy Points:
    0
    CUSTOMER BILLING SYSTEM


    Code:
    #include<stdio.h>
    struct date
     {
     int month;
     int day;
     int year;
     };
    struct account
     {
     char name[50];
     char street[45];
     char city[60];
     int acc_no;
     int acct_type; /* c = current , o = overdue , d = delinquent */
     float oldbalance;
     float newbalance;
     float paymeny;
     struct date lastpayment;
     }
    
    main(   )
    {
    int i ,n ;
    void readinput(int i );
    void writeoutput(int i (;
    printf(“customer billing system \n\n”);
    printf(“how many customer are there ? “ );
    scanf(“%d”,&n);
    for(i=0,i<n,i++)
    {
    readinput(i);
    if(customer[i].payment > 0 )
     customer[i].acct_type =
    (customer[i].oldbalance < 0.1*customer[i].oldbalabce) ? ‘o’ | ‘c’;
    else
     customer[i].acct_type =
     (customer[i].oldbalance > 0 ) ? ‘d’ | ‘c’ ;
    };
    for (i = 0 ; i < n ; i ++)
    writeoutput(i);
    }
    void readinput(int i )
    {
    print(“\n customer no. %d\n”, i+1);
    printf(“ name : “ );
    sccanf(“ %[   ] “,customer[ i ].name);
    printf(“ street : “ ) ;
    scanf(“% [    ] “,customer[ i ] .street);
    printf(“ city : “ );
    scanf(“ %[   ] “,customer[ i ] .city );
    printf(“ account number : “ );
    scanf(%d “ , &customer[ i ] . oldbalance);
    printf( current payment : “);
    scanf(“%f”, &customer[ i ] .payment);
    printf(“ payment date (mm/dd/yyyy) : “);
    scanf(“%d / %d / %d “, &customer[ i ] .lastpayment.month,
        &customer[ i ] .lastpayment.day
    &customer[ i ] .lastpayment.year
    return;
    }
    void writeoutput(int i)
    {
    printf(“ name : %s”, customer[i].name);
    printf(“ account number : %d\n”, customer[i].acct_no);
    printf(“street : %s\n , customer[i].street);
    printf(“city : %s\n\n” , customer[i].city);
    printf(“old balance “ %7.2f”, customer[i].oldbalance);
    printf(“ current payment : %7.2f” , customer[i].payment);
    printf(“ new balance : %7.2f\n\ “,customer[i].newblance);
    printf(“ account status : “);
    switch ( customer[i].acct_type)
    {
    case ‘c’
     printf(“ current\n\n”);
     break;
    case ‘o’
     printf(“ overdue\n\n”); 
     break;
    case ‘d’
     printf(“ delinqunt\n\n”);
     break;
    default;
     printf(“ error \n\n”)
    }
    return;
    }
     

Share This Page